使用python计算测验数据的平均值（疑难解答）

Question

我需要读入学生测验文件中的分数，并返回3次测验中的最高分数。我需要在python中使用hash/dictionary。这是我到目前为止的情况。你知道吗

STD_ID  = {}
ATTEMPTS = {}
SCORE= {}

f= open("std_attempt_score.txt", "r")
line = f.readline()
for line in f:
    line = line.rstrip()
    ents = line.split("\t")
    did = ents[1]
    if did in STD_ID:
            ATTEMPTS[did] += 3
            SCORE[did] += int(ents[2])
    else:
            STD_ID[did]  = ents[2]
            ATTEMPTS[did] = 3
            SCORE[did] = int(ents[2])


for  key in STD_ID:
    print("Avg score for Student", key, "=",SCORE)

文件中的文本数据。你知道吗

FILE
STD_ID  ATT_NUM SCORE
S23Y    1   85
S03X    1   80
S34Z    1   19
S54M    1   23
S34Z    2   25
S01X    1   79
S03X    2   10
S23Y    2   09
S34Z    3   92
S54M    2   96
S23Y    3   74
S54M    3   65
S03X    3   54

我的结果如下：

Avg score for Student 1 = {'1': 286, '2': 140, '3': 285}
Avg score for Student 2 = {'1': 286, '2': 140, '3': 285}
Avg score for Student 3 = {'1': 286, '2': 140, '3': 285}

Answer 1

如果您不需要存储每次尝试的分数，那么如果该值高于当前记录的尝试，为什么不直接替换该值呢？你知道吗

students = {}

f = open("std_attempt_score.txt", "r")
line = f.readline()
for line in f:
    line = line.rstrip()
    ents = line.split(",")
    student_id = ents[0]
    attempt_score = int(ents[2])

    score = students.setdefault(student_id, attempt_score)

    if attempt_score > score:
        students[student_id] = attempt_score


for student_id, score in students.items():
    print("Highest score for Student", student_id, "=", score)