程序运行两次正确使用主程序

2024-05-21 01:02:06 发布

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想知道为什么我的小队函数运行了两次。靠近底部的大多数函数都将前一个函数中的数据作为输入,最后一个函数将查找列表中的最大值。 我想在这里正确地设置main,这样1)在这个程序中,所有的东西都能正常运行;2)当从另一个程序调用时,它只会自己运行squads,并将squads的值返回给那个程序

看起来小队跑了两次,而我的外环打印“iter one done”-两次。既然如此,我应该如何设置我的主要?你知道吗

如何工作-

第一个函数squads返回列表列表
第二个函数-goals\u convert\u dash-获取第一个函数(squads)的输出-获取列表列表中的两个元素(从每个列表中),如果有破折号(-),则将其转换为零。
.Third func-goals\u convert\u toint获取goals\u convert\u dash的输出,并将第二列转换为零。
第四个-get_max然后从第二列中获取最大值,并将其与第一列0中的数据一起输出

如果运行正常,我认为输出应该是-

iter 1完成 英超最佳射手是: [“约翰·史密斯”,11]

我当前的输出是-

iter one done
Premier league top goal scorer is: 
['John Smith', 11]
iter one done

程序-

import requests
from bs4 import BeautifulSoup
import datetime
from operator import itemgetter
from scrape1_squad_urls import table

base_url = 'https://someurl.com'


# Squad Data

team_table = table()

#team_names = team_urls()
def squads():


    strip_team_name = [i.replace('https://www.someurl.com', '') for i in team_table]
    full_strip = [i.replace('-squad', '') for i in strip_team_name]

    iter = 0
    while iter < 1:
        tdstrip = []
        x = []
        tdstripclean = []
        for i in team_table:


                squad_r = requests.get(i)

        #        print(squad_r.status_code)

                now = datetime.datetime.now()
                soup = BeautifulSoup(squad_r.text, 'html.parser')

        #       div = soup.find('div', {'class': '-bp30-box col span1/1'})
                premier_squad_table = premier_squad_soup.find_all('table', {'class': 'table -small no-wrap football-squad-table '})
                headings = []
                playerurls = []
                full_links = []


                strip_team_name = [i.replace('https://someurl.com/', '') for i in team_table]
                full_strip = [i.replace('-squad', '') for i in strip_team_name]
                find_team_name = soup.find('span',{'class': 'swap-text__target'})
                for table in premier_squad_table:

                    table_head = table.find('thead')
                    head_rows = table_head.find_all('tr')

                    for item in head_rows:
                        headers = item.find_all('th')

                    table_body = table.find('tbody')
                    rows = table_body.find_all('tr')
                    for row in rows:
                        td = row.find_all('td')
                        x = [x.text.strip() for x in td]
                        position_teamname = (headers[0].text,find_team_name.text)
                        x[2]
                        x.extend(position_teamname)
                        tdstrip.append(x)
        iter = iter + 1
        print("iter one done")
    return(tdstrip)

#   return(newList)
#squads()

def goals_convert_dash():

    tdstrip = squads()  

    indexes = [0,2]
    newList = [[each_list[i] for i in indexes ] for each_list in tdstrip ]
    for eachlist in newList:
        if eachlist[1] == '-':
            eachlist[1] = 0
    return(newList) 
#goals_convert_dash()



#print(newList)

def goals_convert_toint():
    converted = goals_convert_dash()

    for eachlist in converted:
        eachlist[1] = int(eachlist[1])
    return(converted)        

#goals_convert_toint()


def get_max(lst, i, key_func=None):

    if not key_func: key_func = lambda x: x[i]
    res = max(lst, key=key_func)
    return [res[0], res[i]]

data = goals_convert_toint()

print("Premier league top goal scorer is: ")

print(get_max(data,1, lambda x: int(x[1])))

if __name__ == '__main__':
     squads()
#    goals_convert_dash()
#    goals_convert_toint()
#    get_max()

Tags: 函数nameinconvert列表fortablefind