有没有办法在图表中“切换行/列”数据？

Question

我正在创建一个图表，并希望在PowerPoint中打开图表之前切换已输入数据的行和列。序列的格式和分组不正确，图表以这种方式毫无意义。你知道吗

我使用的是元组，据我所知，元组很难操作，所以如果有一个命令我丢失了，只是切换行/列？这似乎是最简单的解决办法。你知道吗

x3 = Inches(0.3)
y3 = Inches(3.7)
cx3 = Inches(1.25)
cy3 = Inches(1.25)

chart_data_marriage = CategoryChartData()
chart_data_marriage.categories = ['Married HH', 'Married Footprint']

demographics['Profile List Title'] = demographics['Profile List Title'].str.strip()

tuple_married1 = demographics['Family Renters : Users/100 HHs']
tuple_married_footprint = demographics['Profile List: Total Profile Users/100 HHs']


tuple_married1.drop([2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,38,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95], inplace = True)

tuple_married_footprint.drop([2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,38,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95], inplace = True)

chart_data_marriage.add_series('Family Renters : Users/100 HHs', (tuple_married1))
chart_data_marriage.add_series('Profile List: Total Profile Users/100 HHs', (tuple_married_footprint))

marriagechart = storyboard1.shapes.add_chart(XL_CHART_TYPE.DOUGHNUT, x3, y3, cx3, cy3, chart_data_marriage).chart
marriagechart.has_legend = False

在tuple_married1和tuple_married_footprint中，我都有创建甜甜圈图表所需的数据，因此只需按正确的顺序格式化序列。同样，像现在PowerPoint中的按钮这样的切换行和列命令是理想的，否则可能需要更复杂的解决方案。你知道吗

Answer 1

如果数据来自Pandas数据帧，可以在将数据移到pptx之前执行demographics.T。你知道吗

Answer 2

python-pptx没有“pivot chart data”行为，但它很简单，可以完成，而且是一个有趣的难题。你知道吗

如果您以正确的形式插入值（与您输入ChartData的形式几乎相同），那么这样的操作应该可以实现，当然您可以调整它以适应：

original_cats = ("a", "b", "c")
original_sers = (
    ("Series 1", (1, 2, 3)),
    ("Series 2", (4, 5, 6)),
)

new_cats = tuple(ser[0] for ser in original_sers)
#  > ("Series 1", "Series 2")

new_sers = tuple(
    (original_cats[i], (s[1][i] for s in original_sers))
    for i in range(len(original_cats))
)
#  > (("a", (1, 4)), ("b", (2, 5)), ("c", (3, 6)))