元组分组列表

Question

我有这样一个元组列表：

x = [('y', [1, 2]), ('y', [3, 4]), ('y', [5, 6])]

我想还给我这样的东西：

[(1, 2), (3, 4), (5, 6)]

注意：元组数可以不同，也可以是：

x = [('y', [1, 2, 3, 4]), ('y', [5, 6, 7, 8]), ('y', [9, 10, 11, 12]), ('y', [13, 14, 15, 16])]

会产生

[(1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 15, 16)]

Answer 1

使用列表理解获得每个元素的第二项：

new_list = [tuple(b) for a, b in old_list]