Python列表索引值未正确返回

Question

我有一个字符串，我试图得到值“bad”的索引，由于某种原因它抛出了一个错误。你知道吗

>>> s = "This dinner is not that bad!"
>>> l = s.split()
>>> bad_index_value = l.index('bad')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: list.index(x): x not in list

Answer 1

实际上，您的列表中没有bad它的bad!。如果要查找bad的索引，可以使用'!'剥离元素：

>>> s = "This dinner is not that bad!"
>>> s.strip().split()
['This', 'dinner', 'is', 'not', 'that', 'bad!']
>>> 
>>> l=s.strip('!').split()
>>> l.index('bad')
5

Answer 2

>>> s = "This dinner is not that bad !"
>>> l = s.split()
>>> bad_index_value = l.index('bad') # will give you the index.

从技术上讲，bad不存在于您的输入This dinner is not that bad!，它的bad!

Answer 3

>>> import re
>>> s = "This dinner is not that bad!"
>>> re.sub(r'[^\w\s]','',s).split().index('bad')
5
>>>