我试着把第一排末端的雷达图向下移动,这样它就在第一排和第二排之间的中间。我不知道从哪里开始尝试。我已经添加了所需的绘图位置。你知道吗
下面是一些重现问题的代码:
import math
import pandas as pd
import matplotlib.pyplot as plt
import numpy as np
def make_spider(row, title, color, ax=None):
categories=list(radar_dfs)
N = len(categories)
angles = np.arange(N+1)/N*2*np.pi
values=radar_dfs.iloc[row].values.flatten().tolist()
values += values[:1]
ax.plot(angles, values, color=color,linewidth=2, linestyle='solid')
ax.fill(angles, values, color=color, alpha=0.4)
radar_dfs = pd.DataFrame.from_dict({"no_rooms":{"0":-0.3470532925,"1":-0.082144001,"2":-0.082144001,"3":-0.3470532925,"4":-0.3470532925},"total_area":{"0":-0.1858487321,"1":-0.1685491141,"2":-0.1632483955,"3":-0.1769700284,"4":-0.0389887094},"car_park_spaces":{"0":-0.073703681,"1":-0.073703681,"2":-0.073703681,"3":-0.073703681,"4":-0.073703681},"house_price":{"0":-0.2416123064,"1":-0.2841806825,"2":-0.259622004,"3":-0.3529449824,"4":-0.3414842657},"pop_density":{"0":-0.1271390651,"1":-0.3105853643,"2":-0.2316607937,"3":-0.3297832328,"4":-0.4599021194},"business_rate":{"0":-0.1662745006,"1":-0.1426329043,"2":-0.1577528867,"3":-0.163560133,"4":-0.1099718326},"noqual_pc":{"0":-0.0251535462,"1":-0.1540641646,"2":-0.0204666924,"3":-0.0515740013,"4":-0.0445135996},"level4qual_pc":{"0":-0.0826103951,"1":-0.1777759951,"2":-0.114263357,"3":-0.1787044751,"4":-0.2709496389},"badhealth_pc":{"0":-0.105481688,"1":-0.1760349683,"2":-0.128215043,"3":-0.1560577648,"4":-0.1760349683}})
fig, axes = plt.subplots(2, 3, subplot_kw=dict(polar=True), sharey=True,
figsize=(28,20))
palette =['#79BD9A','#69D2E7','#F38630', '#547980','#EDC951']
labels = ['A', 'B', 'C', 'D', 'E']
row_one = axes.flatten()
for row, (ax, letter, col) in enumerate(zip(row_one, labels, palette)):
make_spider( row = row, title='Group ' + str(letter), color=col, ax=ax)
fig.delaxes(axes[1][2])
plt.subplots_adjust(wspace=.4, hspace=.3)
plt.show()
有人有什么建议吗?你知道吗
一种方法是使用
plt.subplot2grid()
创建每个子批并手动定位它们。可以使用的技巧是将每个图表的行数和高度增加一倍,这样可以更精细地调整位置。你知道吗在这个解决方案中,
sharey
必须手动设置。也许一个更干净的方法是使用ax.get_shared_y_axes().join(*axes)
(检查here)。你知道吗希望有帮助。你知道吗
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