基数为10的int（）的文本无效：“i”：跳转程序

Question

以10为基数的int（）的文本无效：“i”每次运行程序都会导致此错误有解决方案吗？你知道吗

def jumpIt(lst, n, k, i):
    res = min(n, k) + (int(lst[i]))
    k = n
    n = res
    i = i + 1
    if(i < len(lst)):
        jumpIt(lst, n, k, i)
    else:
        print(res)

def main():
    fileName = "input.txt"
    for line in fileName:
        lst = line.split()
        jumpIt(lst, 0, 0, 0)

main()

Answer 1

您没有打开文件进行读取。不读取文件内容，而是读取其名称（当然，名称不包含数字）。以下是您真正需要的：

def main():
    fileName = "input.txt"
    with open(fileName) as infile:
        for line in infile:
            lst = line.split()
            jumpIt(lst, 0, 0, 0)