我和人工智能一起工作,得到了一个与一年中的时间相关的数据集。用另一个词。温度、压力、湿度等。任务包括确定季节性关闭数据。我做了些调查。详情见所附代码。从天文学的角度来看,是否有任何共同的数据类型来表示季节和一天中的时间?你知道吗
我已经试过用三角函数sin和cos来表示数据了。你知道吗
# # The way to represent season.
import pandas as pd
import math
rng = pd.date_range('1/1/2011', periods=365*3, freq='D')
# Time of year is close to what I want, but...
rng[100+2].dayofyear - rng[100].dayofyear
# Out: 2
# ...in some cases it goes wrong:
# Only 2 days range. Almost no difference from the season point of
# view.
rng[364+2].dayofyear - rng[364].dayofyear
# Out: -363
# Yes, of couse, we still have a chance to fit AI to distinguish what
#'season' mean. But isn't it to complicate? In fact I want to
# reproduce some kind of astronomical data.
df = pd.DataFrame(index=rng, columns=('dayofyear','sin','cos'))
# Yes, I no this is not optimal. But this is just for visibility
for day in rng:
#print (day.dayofyear)
df.loc[day, 'dayofyear']=day.dayofyear
df.loc[day, 'sin'] = math.sin(day.dayofyear/365*2*math.pi)
df.loc[day, 'cos'] = math.cos(day.dayofyear/365*2*math.pi)
# Now, we can see something like season mean:
( df.loc['2012-01-01', 'sin'] - df.loc['2011-12-31', 'sin'] ) *
( df.loc['2012-01-01', 'cos'] - df.loc['2011-12-31', 'cos'] )
# Out: -2.5503444618122675e-06
( df.loc['2012-06-01', 'sin'] - df.loc['2011-12-31', 'sin'] ) *
( df.loc['2012-06-01', 'cos'] - df.loc['2011-12-31', 'cos'] )
# Out: -0.9111812528724549
# But, may be I just reinvent the bicycle?
# Is there a proper way to reproduce season and "Times of Day"?
据我所知,season在timestamp的数据类型或time模块中没有被确认。你知道吗
你能做的就是写一个forumala来评估日期,并确定它属于哪个季节。你知道吗
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