如何将序数添加到文本fi中每行的开头

Question

我有一个存储在文件中的游戏排行榜。文件格式如下：

bob has 46 points fred has 0 points leo has 27 points

我有这个代码来显示从升序到降序的分数：

if ens == "s":
    print("\n"+"LeaderBoard: "+"\n")
    f = open("scores.txt","r")
    lines = list(f) #create a list of strings
    f.close() #don't forget to close our files when we're done. It's good practice.
    modified_lines = [] #empty list to put our modified lines in (extracted number, original line)
    for line in lines: #iterate over each line
        if line.strip(): #if there's anything there after we strip away whitespace
            score = line.split(' ')[2] #split our text on every space and take the third item
            score = int(score) #convert the string of our score into a number
            modified_lines.append([score, line]) #add our modified line to modified_lines

    #sort our list that now has the thing we want to sort based on is first
    sorted_modified_lines = sorted(modified_lines, reverse = True )

    #take only the string (not the number we added before) and print it without the trailing newline.
    for line in sorted_modified_lines: print(line[1].strip()+"\n")

输出：

bob has 46 points leo has 27 points fred has 0 points

我想要的是在分数前面显示序号，如下所示：

1st. bob has 46 points 2nd. leo has 27 points 3rd. fred has 0 points

我看过其他的文章，展示了如何显示序数，但我仍然不知道如何做到这一点。你知道吗

Answer 1

将最后一行替换为下面的两行，序号作为here的引用

suf = lambda n: "%d%s"%(n,{1:"st",2:"nd",3:"rd"}.get(n if n<20 else n%10,"th"))

for index, line in enumerate(sorted_modified_lines): print(suf(index + 1) + '. ' + line[1].strip()+"\n")

Answer 2

我觉得你被否决了，因为看起来你没有那么努力，你也没有说你做了什么，但你还是来了：像这样的事情。。。你知道吗

def ordinal_string(i):
   if i >= 10 and i <= 20:
      suffix = 'th'
   else:
     il = i % 10
     if il == 1:
        suffix = 'st'
     elif il == 2:
        suffix = 'nd'
     elif il == 3:
        suffix = 'rd'
     else:
        suffix = 'th'
   return str(i) + suffix + '. '

然后：

for i, line in enumerate(sorted_modified_lines): print(ordinal_string(i+1) + line[1].strip()+"\n")