在Flas中调用重定向时获取意外的关键字参数“mimetype”

2024-04-25 22:31:12 发布

您现在位置：Python中文网/ 问答频道 /正文
9725 3

我在python Flask中有一个restapi，它应该将一个字符串作为响应发布到先前定义的回调URL。这是我的密码：

return redirect(
    location=callback_url,
    code=200,
    Response=Response(status=200, response="Zeinab,Abbasimazar,1989,Sep,07")
)

但控制台出现以下错误：

[2019-12-25 18:15:07,482] ERROR in app: Exception on /v1/PaymentPage [POST]
Traceback (most recent call last):
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 2446, in wsgi_app
    response = self.full_dispatch_request()
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1951, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1820, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/_compat.py", line 39, in reraise
    raise value
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1949, in full_dispatch_request
    rv = self.dispatch_request()
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1935, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/zeinab/PycharmProjects/paygate_service_rest/server.py", line 323, in payment_page
    Response=Response(status=200, response=transaction.get_transaction_result_string(res_code=0))
  File "/home/zeinab/.local/lib/python3.6/site-packages/werkzeug/utils.py", line 506, in redirect
    mimetype="text/html",
TypeError: __call__() got an unexpected keyword argument 'mimetype'

当我跟踪代码时，这是在库中方法redirect的文件python3.6/site-packages/werkzeug/utils.py中设置的：

response = Response(
    '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">\n'
    "<title>Redirecting...</title>\n"
    "<h1>Redirecting...</h1>\n"
    "<p>You should be redirected automatically to target URL: "
    '<a href="%s">%s</a>.  If not click the link.'
    % (escape(location), display_location),
    code,
    mimetype="text/html",
)

我已将代码更改为：

return redirect(
    location=callback_url,
    code=200,
    Response="Zeinab,Abbasimazar,1989,Sep,07"
)

现在我得到：

[2019-12-25 18:26:01,109] ERROR in app: Exception on /v1/PaymentPage [POST]
Traceback (most recent call last):
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 2446, in wsgi_app
    response = self.full_dispatch_request()
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1951, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1820, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/_compat.py", line 39, in reraise
    raise value
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1949, in full_dispatch_request
    rv = self.dispatch_request()
  File "/home/zeinab/.local/lib/python3.6/site-packages/flask/app.py", line 1935, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/zeinab/PycharmProjects/paygate_service_rest/server.py", line 324, in payment_page
    Response=msg
  File "/home/zeinab/.local/lib/python3.6/site-packages/werkzeug/utils.py", line 506, in redirect
    mimetype="text/html",
TypeError: 'str' object is not callable

如何跳过mimetype标题或更改它？我的图书馆需要升级吗？你知道吗


Tags： inpyselfappflaskhomerequestlib
1条回答
网友
1楼 · 发布于 2024-04-25 22:31:12
return redirect(
    location=callback_url,
    code=200,
    Response=Response(status=200, response="Zeinab,Abbasimazar,1989,Sep,07")
)

flask.redirect()的only supported status codes是301、302、303、305、307和308。所有HTTP重定向都从3xx开始。我不确定具体异常的确切原因，但这很可能就是原因。如果非要猜测的话，Flask不希望重定向请求中出现mimetype，因为HTTP重定向（至少，Flask支持的重定向）没有主体，只有头。尝试将代码更新为：

return redirect(location=callback_url, code=302)

HTTP状态为200告诉浏览器请求成功，并且应该呈现正文中返回的内容。一些响应（如4xx响应）也可以有一个主体，因为尽管发生了错误，服务器仍可以返回HTML供浏览器呈现（如自定义404页）。但是，大多数3xx代码不允许有正文，而是应该有一个Location头，浏览器在收到请求时将导航到该头。正文中的内容将被忽略。HTTP状态码的有用列表可以在here中找到。你知道吗

关于问题的后半部分，当您第二次更改代码时，将Response参数替换为以下内容：

Response="Zeinab,Abbasimazar,1989,Sep,07"

您最初所做的是正确的（除了响应代码）flask.redirect方法正在为Response参数寻找一个类型为Response的对象（我知道很混乱），但是您正在传入一个类型为str的对象。你知道吗

希望这有帮助。你知道吗

TLDR:将code方法的redirect参数更改为支持的重定向状态代码之一，并且不要尝试返回响应正文。

相关问题 更多 >

    编程相关推荐