在python中提取字符串的一部分有限制

Question

我有一个字符串输出，如下所示：

Distance AAAB: ,0.13634,0.13700,0.00080,0.00080,-0.00066,.00001,
Distance AAAC: ,0.12617,0.12680,0.00080,0.00080,-0.00063,,
Distance AAAD: ,0.17045,0.16990,0.00080,0.00080,0.00055,,
Distance AAAE: ,0.09330,0.09320,0.00080,0.00080,0.00010,,
Distance AAAF: ,0.21048,0.21100,0.00080,0.00080,-0.00052,,
Distance AAAG: ,0.02518,0.02540,0.00040,0.00040,-0.00022,,
Distance AAAH: ,0.11404,0.11450,0.00120,0.00110,-0.00046,,
Distance AAAI: ,0.10811,0.10860,0.00080,0.00070,-0.00049,,
Distance AAAJ: ,0.02430,0.02400,0.00200,0.00200,0.00030,,
Distance AAAK: ,0.09449,0.09400,0.00200,0.00100,0.00049,,
Distance AAAL: ,0.07689,0.07660,0.00050,0.00050,0.00029,

我想做的是从这个块中提取一组特定的数据，例如仅距离AAAH，如下所示：

Distance AAAH: ,0.11404,0.11450,0.00120,0.00110,-0.00046,,

测量总是从距离AAA*开始：恒星是唯一会改变的字符。你知道吗

并发症： 这需要是通用的，因为我有很多不同的数据集，所以距离AAAH可能并不总是跟在距离AAAI后面或者跟在距离AAAG前面，因为不同项目的测量值是不同的。我也不能依赖于.len（），因为最后一次测量有时可以是空白的（如距离AAAH），也可以是填充的（如距离AAAB）。我想我不能使用.find（），因为我需要所有跟在距离后面的数字。你知道吗

我还是个新手，我尽了最大努力找到了一个类似于这个问题的解决方案，但运气不太好。你知道吗

Answer 1

您可以使用re模块。做一个函数应该很方便。你知道吗

import re
def SearchDistance(pattern,text):
    pattern = pattern.replace(' ','\s')
    print re.findall(r'{0}.+'.format(pattern),a)

SearchDistance('Distance AAAH',a)

输出：

['Distance AAAH: ,0.11404,0.11450,0.00120,0.00110,-0.00046,,']

Answer 2

您可以通过以下脚本搜索文本：

#fullText = YOUR STRING
text = fullText.splitlines()
for line in text:
    if line.startswith('Distance AAAH:'):
        print line

输出：Distance AAAH: ,0.11404,0.11450,0.00120,0.00110,-0.00046,,