如何删除重复的打印语句问题并转到下一行。输出应该是这样的。你知道吗
当前我的打印输出如下所示:
Assign
Key, Summary , Reporter , Name , Resolution , Createdate , UpdateDate , Due , Team
Assign
Key, Summary , Reporter , Name , Resolution , Createdate , UpdateDate , Due , Team
...
我希望输出像这样,没有任何重复。
Assign
Key, Summary , Reporter , Name , Resolution , Createdate , UpdateDate , Due ,Team
Key, Summary , Reporter , Name , Resolution , Createdate , UpdateDate , Due , Team
...
我的代码是这样的
def assigne(username):
responses = fetch(server + Ticket_Week + ' and assignee='+ username)
duplicate = []
object = {}
for issue in responses['issues']:
issue_fields = issue['fields']
issue_status = issue_fields['status']
issue_reporter = issue_fields['reporter']['displayName']
issue_created = issue_fields['created']
issue_updated = issue_fields['updated']
issue_assign = 'Unassigned'
issue_resolution = 'Unresolved'
issue_due = 'null'
issue_serviceteam = 'null'
issue_createdate = datetime.datetime.strptime(issue_created[:-5], '%Y-%m-%dT%H:%M:%S.%f').strftime("%m/%d/%y")
issue_updatedate = datetime.datetime.strptime(issue_updated[:-5], '%Y-%m-%dT%H:%M:%S.%f').strftime("%m/%d/%y")
if issue_fields['assignee']:
issue_assign = issue_fields['assignee']['displayName']
if issue_fields['resolution']:
issue_resolution = issue_fields['resolution']['name']
if issue_fields.get('duedate', None):
issue_due = issue_fields['duedate']
if issue_fields.get('customfield_10506', None):
issue_serviceteam = issue_fields['customfield_10506']['name']
print(issue_assign)
print(issue['key'], issue_fields['summary'], issue_reporter, issue_status['name'], issue_resolution, issue_createdate, issue_updatedate, issue_due, issue_serviceteam)
如果您的问题是
print(issue_assign)
,请引入布尔变量i
:编辑(基于评论):
如果你有多个用户,你有多种选择,但我要强调两个:
假设您的用户名是1、2、3和4:
在我看来,另一个选择是更好的解决方案:
通过这种方式,您可以将用户名作为单个用户名转发,也可以使用用户名列表调用函数。你知道吗
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