分析一个关键字的.txt文件，然后寻找子关键字？

Question

很抱歉，我不知道该如何正确回答这个问题。你知道吗

我有一个脚本，从思科交换机拉配置保存到一个.txt文件，我想提取关键信息。下面是提取的.txt文件的摘录：

!
!
!
!
interface Port-channel10
!
interface GigabitEthernet0/0
 description ** Uplink to C1 **
 switchport trunk allowed vlan 95
 switchport trunk encapsulation dot1q
 switchport mode trunk
 media-type rj45
 negotiation auto
!
interface GigabitEthernet0/1
 description ** Uplink to C2 **
 switchport trunk allowed vlan 95
 switchport trunk encapsulation dot1q
 switchport mode trunk
 media-type rj45
 negotiation auto
 channel-group 10 mode auto
!
interface GigabitEthernet0/2
 description ** Downlink to NetAuto **
  switchport access vlan 95
  switchport mode access
  media-type rj45
  negotiation auto
!
interface GigabitEthernet0/3
 switchport trunk encapsulation dot1q
 media-type rj45
 negotiation auto
 channel-group 10 mode auto
!
interface GigabitEthernet1/0
 media-type rj45
 negotiation auto
!
interface GigabitEthernet1/1
 media-type rj45

我希望从上述.txt文件中提取以下信息：

• 接口信息（所有）
• 描述（如果存在）
• 通道组编号（如果存在）

我希望的一个输出示例是：

interface GigabitEthernet0/0
 description ** Uplink to C1 **
interface GigabitEthernet0/1
 description ** Uplink to C2 **
 channel-group 10
interface GigabitEthernet0/2
 description ** Downlink to NetAuto **

等等。。。你知道吗

不过，下面是我当前的代码，它没有给我任何我想要的东西，我对有限的python知识完全没有想法：

with open('newfile1', 'r') as fi:
    int = []
    desc = []
    for ln in fi:
        if ln.startswith("interface"):
            int = (ln)
            print(int) 
            for ln in fi: 
                if ln.startswith(" description"): 
                    desc = (ln) 
                    print(desc) 

这将返回：

interface Port-channel10

 description ** Uplink to C1 **

 description ** Uplink to C2 **

 description ** Downlink to NetAuto **

Answer 1

保持简单-将文本文件拆分为行，将行拆分为单词，检查第一个单词是否在您感兴趣的单词列表中。你知道吗

results = []
first_words = ['interface', 'description', 'channel-group']
input_file = 'switch.txt'

with open(input_file, 'r') as switch_file:
    for line in switch_file.readlines():
        words_in_line = line.split()
        # There should be at least 1 word in the line
        if 0 < len(words_in_line):
            first_word = words_in_line[0]
            if any(first_word in s for s in first_words):
                results.append(line.rstrip())

print("\n".join(results))

输出：

interface Port-channel10
interface GigabitEthernet0/0
 description ** Uplink to C1 **
interface GigabitEthernet0/1
 description ** Uplink to C2 **
 channel-group 10 mode auto
interface GigabitEthernet0/2
 description ** Downlink to NetAuto **
interface GigabitEthernet0/3
 channel-group 10 mode auto
interface GigabitEthernet1/0
interface GigabitEthernet1/1