用max打印numpy数组的索引

Question

我想打印出具有最大值的数组的索引（由于索引从0开始，我需要在索引值中添加一个以获得1索引）。示例：

rslt = np.amax(final_array)
print("The maximum value is :", rslt)
print("The optimal choice that has that value is :", rslt.index[])

---

上下文：我正在用Python编写一些多准则决策分析代码。我导入numpy来处理备选方案、标准和权重的数组。我用np.amax公司在最终数组中查找最大值。你知道吗

Answer 1

使用numpy.argmax查找最大值的索引。你知道吗

Answer 2

import numpy as np

#some list
f = [1,2,3,4,5,6,6,6,6,6]

#max value
print (f"the max value is : { np.amax(f)}")

#indices where max values are located
max_indices = np.argwhere( f == np.amax(f))

#adding 1 to get position
max_positions = [i+1 for i in max_indices.flatten().tolist()]

print(f"Max values are located at : {max_positions}")

#first max value
print(f"First max value occurs at : {max_positions[0]}")