读取日志文件并打开

Question

我在读取用另一种方法创建的日志文件时遇到问题。 日志文件中有解压文件的文件路径（解包在另一个函数中）。日志文件看起来像这样

/home/usr/Downloads/outdir/Code/XXX.something
/home/usr/Downloads/outdir/Code/YYY.something
/home/usr/Downloads/outdir/Code/AAA.something

---

@staticmethod
def iterate_log(path):
    results = str()
    for dirpath, dirnames, files in os.walk(path):
        for name in files:
            results += '%s\n' % os.path.join(dirpath, name)
    with open(os.path.join(EXTRACT_PATH_, LOGNAME_), 'w') as logfile:
        logfile.write(results)
        return os.path.join(EXTRACT_PATH_, LOGNAME_)

@staticmethod
def read_received_files(from_file):
    with open(from_file, 'r') as data:
        data = data.readlines()
        for lines in data:
        # to reduce confusion I would use
        # for line in data:
            read_files = open(lines)
            print(read_files)
            return read_files

现在我想逐行读取日志文件（第二个方法中的参数from_files是第一个方法的返回值），打开这些文件并返回它们（在其他地方使用它们）。 readlines()和read()到目前为止都给了我错误

readlines() = [Errno2] No sucht file or directory: '/../../../logfile.log\n

read() = IsADirectoryError: [Errno21]

全回溯：

    Traceback (most recent call last):
  File "files_received_test.py", line 13, in <module>
    main()
  File "files_received_test.py", line 9, in main
    j = Filesystem.execute_code(FILENAME_)
  File "/home/usr/PycharmProjects/Projektgruppe/code/src/filesystem_hasher.py", line 16, in execute_code
    Filesystem.read_received_files(create_log)
  File "/home/usr/PycharmProjects/Projektgruppe/code/src/filesystem_hasher.py", line 54, in read_received_files
    read_files = open(lines)
FileNotFoundError: [Errno 2] No such file or directory: '/home/usr/Downloads/outdir/unpacked_files.log\n'

Answer 1

你只需要去掉换行符就可以了

read_files = open(lines)

至

read_files = open(lines.strip())

作为一个观察结果（对于读取错误消息中的每个字符都很关键），该消息告诉您没有名为

'/home/usr/Downloads/outdir/unpacked_files.log\n'

因此，尝试理解\n出现的原因非常有用-这与您对文件名的期望不符，因此您应该想知道为什么文件具有该名称