创建取决于变量的列表

Question

实际上我有一个问题，因为我想在函数中创建一个列表，但它取决于一个变量，我的意思是。。。有了一个输入，我想定义变量的值，有了代码，我模拟了一家餐馆的程序，为一张桌子提供服务，我应该能够把他们要的食物添加到每一张桌子的列表中。这是我的代码：

foodlist = []
table_1 = []
table_2 = []
table_3 = []
table_4 = []
table_5 = []
table_6 = []
p = 0

def openFile():
    file = open("cartarest.txt","r",1,"utf-8")
    line = file.readline().strip()
    while line != "":    
        parts = line.split(";")
        name = parts[0]
        price = int(parts[1])
        type = parts[2]     
        foodlist.append(parts)
        line = file.readline().strip()
        p += 1
    return (foodlist,p)

def serveTable(x):
    print("The menu of the restaurant is:")
    print(foodlist)
    add = input("Which food do you want to add?: ")
    while add != 0:
        for i in range(p):
            if add.lower() == foodlist[i][0]:
                **table_+x.append(foodlist[i])**
        add = input("Which food do you want to add?: ")

openFile()
tableserve = input("What table do you want to attend?")
while tableserve.lower() != "cerrar":
    serveTable(tableserve)
    tableserve = input("What table do you want to attend?")

EDIT：我已经解决了变量'p'的问题，但是现在我有一个问题，如何限制表的范围，因为我试着输入一个像“-1”这样的值，并且代码正常运行，它不应该工作，只使用1到6之间的值（显然使用@Tim的答案）

Answer 1

使用列表列表代替6个表变量，并将表编号作为索引传递：

tables = [[] for _ in range(ntables)]
def serveTable(x):
    print("The menu of the restaurant is:")
    print(foodlist)
    add = input("Which food do you want to add?: ")
    while add != 0:
        for i in range(p):
            if add.lower() == foodlist[i][0]:
                tables[x].append(foodlist[i])
        add = input("Which food do you want to add?: ")