如何使用python按递增顺序编写数字列表

Question

我有一张单子

a1 = ['1', '5-10', '12', '18', '23', '100-110', '16-17', '20']

我要这个元素列表按递增顺序排列 就像

a1 = ['1','5-10','12','16-17','18','20','23','100-110']

有人能帮我安排一下吗

case = ['1', '5-10', '12', '18', '23', '100-110', '16-17', '20']
case1 = [i.split('-', 1)[0] for i in case]
case1 = [int(x) for x in case1]

case1.sort()

打印后，case1输出为

[1, 5, 12, 16, 18, 20, 23 ,100]

但我希望输出像

[1, 5-10, 12, 16-17, 18, 20, 23, 100-110]

Answer 1

如果确定每个列表元素应该是整数字符串或由整数组成的破折号分隔的字符串，可以尝试以下操作：

a_dict = {int(v.split('-')[0]): v for v in a}
final_a = [a_dict[k] for k in sorted(a_dict)]
print final_a

那就回来了

['1', '5-10', '12', '16-17', '18', '20', '23', '100-110']