将列表中的元素排序为3个单独的列表

Question

让我从代码开始，解释一下目标和我得到了什么。你知道吗

temp1 = ['3.8', 'Weiss, Earl', '139 RATINGS', '2.3', 'Jeppson, Catherine', '114 RATINGS', '3.3', 'Kiani-Aslani, Rajabali', '88 RATINGS', '2.6', 'Lundblad, Heidemarie', '82 RATINGS', '2.4', 'Stone, Ronald', '75 RATINGS', '3.7', 'Vedd, Rishma', '66 RATINGS', '3.3', 'Foster, Robert', '60 RATINGS', '4.9', 'Basmadzhyan, Babken', '59 RATINGS', '4.3', 'Grodsky, Marilyn', '57 RATINGS', '2.4', 'Dorsey, Norris', '53 RATINGS', '2.6', 'Zvinakis, Kristina', '51 RATINGS', '3.2', 'MacKlin, James', '50 RATINGS', '2.8', 'Liu, David', '48 RATINGS', '3.2', 'Doron, Michael', '48 RATINGS', '2.1', 'Rogoff, Donald', '45 RATINGS', '3.1', 'Sangeladji, Mohammad', '43 RATINGS', '4.0', 'Fountaine, Howard', '42 RATINGS', '4.6', 'Stout, Gary', '41 RATINGS', '3.4', 'Gray, Glen', '34 RATINGS', '3.0', 'Wilson, Barbara', '31 RATINGS', '4.0', 'Yoon, Sung-Wook', '31 RATINGS', '4.5', 'Her, Young-Won', '31 RATINGS', '3.0', 'Kiddoo, Robert', '30 RATINGS', '3.0', 'Chiu, J', '27 RATINGS', '3.3', 'Barker, Robert', '25 RATINGS', '3.7', 'Qureshi, Mahmood', '23 RATINGS', '3.7', 'Primes, David', '22 RATINGS', '2.6', 'Chen, Raymond', '20 RATINGS', '3.3', 'Jones, Christopher', '20 RATINGS', '3.2', 'Zhan, Jun', '20 RATINGS', '4.6', 'Bell, Janice', '15 RATINGS', '3.8', 'Alhashim, Dhia D', '12 RATINGS', '2.9', 'Ansari, Shahid', '11 RATINGS', '4.5', 'Rousselet, Robin (rob)', '9 RATINGS', '2.4', 'Lucero, Terrence', '8 RATINGS', '1.0', 'Perez, Marlene', '7 RATINGS', '1.3', 'Crespo, Patricia', '7 RATINGS', '4.8', 'Knight, Ridgeway', '7 RATINGS', '2.5', 'Julius, Ed', '6 RATINGS', '2.9', 'Reinstein, Todd', '6 RATINGS']

所以我的目标是把这个巨大的列表分成3个不同的分类列表

教授姓名、教授评级和评级金额

我用下面的if语句开发了下面的for循环，尽管尝试使用它至少有一个不起作用，让我在下面的代码中向您展示

counter = 1
for index in temp1:
    if counter % 1 == 0:
        pro_rating.append(index)
    if counter % 2 == 0:
        pro_name.append(index)
    if counter % 3 == 0:
        pro_amount_rating.append(index)
        counter = 0
    counter += 1

print("All Professor ratings: ", pro_rating)    
print("All professor names: ", pro_name)
print("Amount of times professor rated: ", pro_amount_rating)

现在，在添加姓名（pro\u姓名）和评级金额（pro\u金额\u评级）时，一切都很顺利，但pro\u评级总是写出完整的列表。你知道吗

我完全理解为什么会发生这种情况，这是因为我正在重置计数器，一旦它达到3，我的计数器在最后加1，使第一个if语句始终为真。你知道吗

我想放置一个标志或第二个参数来解决这个问题，但我似乎无法解决它，我知道我可以很容易地使另一个forloop来解决这个问题，但我想让他们都在这个单一的for循环完成。你知道吗

如果有人有任何想法，我将不胜感激！你知道吗

输出：

All Professor ratings:  ['3.8', 'Weiss, Earl', '139 RATINGS', '2.3', 'Jeppson, Catherine', '114 RATINGS', '3.3', 'Kiani-Aslani, Rajabali', '88 RATINGS', '2.6', 'Lundblad, Heidemarie', '82 RATINGS', '2.4', 'Stone, Ronald', '75 RATINGS', '3.7', 'Vedd, Rishma', '66 RATINGS', '3.3', 'Foster, Robert', '60 RATINGS', '4.9', 'Basmadzhyan, Babken', '59 RATINGS', '4.3', 'Grodsky, Marilyn', '57 RATINGS', '2.4', 'Dorsey, Norris', '53 RATINGS', '2.6', 'Zvinakis, Kristina', '51 RATINGS', '3.2', 'MacKlin, James', '50 RATINGS', '2.8', 'Liu, David', '48 RATINGS', '3.2', 'Doron, Michael', '48 RATINGS', '2.1', 'Rogoff, Donald', '45 RATINGS', '3.1', 'Sangeladji, Mohammad', '43 RATINGS', '4.0', 'Fountaine, Howard', '42 RATINGS', '4.6', 'Stout, Gary', '41 RATINGS', '3.4', 'Gray, Glen', '34 RATINGS', '3.0', 'Wilson, Barbara', '31 RATINGS', '4.0', 'Yoon, Sung-Wook', '31 RATINGS', '4.5', 'Her, Young-Won', '31 RATINGS', '3.0', 'Kiddoo, Robert', '30 RATINGS', '3.0', 'Chiu, J', '27 RATINGS', '3.3', 'Barker, Robert', '25 RATINGS', '3.7', 'Qureshi, Mahmood', '23 RATINGS', '3.7', 'Primes, David', '22 RATINGS', '2.6', 'Chen, Raymond', '20 RATINGS', '3.3', 'Jones, Christopher', '20 RATINGS', '3.2', 'Zhan, Jun', '20 RATINGS', '4.6', 'Bell, Janice', '15 RATINGS', '3.8', 'Alhashim, Dhia D', '12 RATINGS', '2.9', 'Ansari, Shahid', '11 RATINGS', '4.5', 'Rousselet, Robin (rob)', '9 RATINGS', '2.4', 'Lucero, Terrence', '8 RATINGS', '1.0', 'Perez, Marlene', '7 RATINGS', '1.3', 'Crespo, Patricia', '7 RATINGS', '4.8', 'Knight, Ridgeway', '7 RATINGS', '2.5', 'Julius, Ed', '6 RATINGS', '2.9', 'Reinstein, Todd', '6 RATINGS']
All professor names:  ['Weiss, Earl', 'Jeppson, Catherine', 'Kiani-Aslani, Rajabali', 'Lundblad, Heidemarie', 'Stone, Ronald', 'Vedd, Rishma', 'Foster, Robert', 'Basmadzhyan, Babken', 'Grodsky, Marilyn', 'Dorsey, Norris', 'Zvinakis, Kristina', 'MacKlin, James', 'Liu, David', 'Doron, Michael', 'Rogoff, Donald', 'Sangeladji, Mohammad', 'Fountaine, Howard', 'Stout, Gary', 'Gray, Glen', 'Wilson, Barbara', 'Yoon, Sung-Wook', 'Her, Young-Won', 'Kiddoo, Robert', 'Chiu, J', 'Barker, Robert', 'Qureshi, Mahmood', 'Primes, David', 'Chen, Raymond', 'Jones, Christopher', 'Zhan, Jun', 'Bell, Janice', 'Alhashim, Dhia D', 'Ansari, Shahid', 'Rousselet, Robin (rob)', 'Lucero, Terrence', 'Perez, Marlene', 'Crespo, Patricia', 'Knight, Ridgeway', 'Julius, Ed', 'Reinstein, Todd']
Amount of times professor rated:  ['139 RATINGS', '114 RATINGS', '88 RATINGS', '82 RATINGS', '75 RATINGS', '66 RATINGS', '60 RATINGS', '59 RATINGS', '57 RATINGS', '53 RATINGS', '51 RATINGS', '50 RATINGS', '48 RATINGS', '48 RATINGS', '45 RATINGS', '43 RATINGS', '42 RATINGS', '41 RATINGS', '34 RATINGS', '31 RATINGS', '31 RATINGS', '31 RATINGS', '30 RATINGS', '27 RATINGS', '25 RATINGS', '23 RATINGS', '22 RATINGS', '20 RATINGS', '20 RATINGS', '20 RATINGS', '15 RATINGS', '12 RATINGS', '11 RATINGS', '9 RATINGS', '8 RATINGS', '7 RATINGS', '7 RATINGS', '7 RATINGS', '6 RATINGS', '6 RATINGS']

已解决： 谢谢你，迈克尔，我想得太清楚了，用了一个简单的 计数器==1，2。。。解决了这个问题，而不是再次使用模

Answer 1

将行counter % 1 == 0更改为counter % 3 == 0会更干净。记住，你需要每三个元素，所以你要用3取模，并检查余数是0。你知道吗

然后可以停止重置第三个if块中的计数器，并将其更改为counter % 3 == 2。我将把它作为一个练习来计算中间if块应该是什么。你知道吗

Answer 2

您可以创建一个嵌套列表，存储评分、教授姓名以及教授被评分的次数：

from collections import namedtuple
import re
professor = namedtuple('professor', ['rating', 'name', 'ratings'])
d = ['3.8', 'Weiss, Earl', '139 RATINGS', '2.3', 'Jeppson, Catherine', '114 RATINGS', '3.3', 'Kiani-Aslani, Rajabali', '88 RATINGS', '2.6', 'Lundblad, Heidemarie', '82 RATINGS', '2.4', 'Stone, Ronald', '75 RATINGS', '3.7', 'Vedd, Rishma', '66 RATINGS', '3.3', 'Foster, Robert', '60 RATINGS', '4.9', 'Basmadzhyan, Babken', '59 RATINGS', '4.3', 'Grodsky, Marilyn', '57 RATINGS', '2.4', 'Dorsey, Norris', '53 RATINGS', '2.6', 'Zvinakis, Kristina', '51 RATINGS', '3.2', 'MacKlin, James', '50 RATINGS', '2.8', 'Liu, David', '48 RATINGS', '3.2', 'Doron, Michael', '48 RATINGS', '2.1', 'Rogoff, Donald', '45 RATINGS', '3.1', 'Sangeladji, Mohammad', '43 RATINGS', '4.0', 'Fountaine, Howard', '42 RATINGS', '4.6', 'Stout, Gary', '41 RATINGS', '3.4', 'Gray, Glen', '34 RATINGS', '3.0', 'Wilson, Barbara', '31 RATINGS', '4.0', 'Yoon, Sung-Wook', '31 RATINGS', '4.5', 'Her, Young-Won', '31 RATINGS', '3.0', 'Kiddoo, Robert', '30 RATINGS', '3.0', 'Chiu, J', '27 RATINGS', '3.3', 'Barker, Robert', '25 RATINGS', '3.7', 'Qureshi, Mahmood', '23 RATINGS', '3.7', 'Primes, David', '22 RATINGS', '2.6', 'Chen, Raymond', '20 RATINGS', '3.3', 'Jones, Christopher', '20 RATINGS', '3.2', 'Zhan, Jun', '20 RATINGS', '4.6', 'Bell, Janice', '15 RATINGS', '3.8', 'Alhashim, Dhia D', '12 RATINGS', '2.9', 'Ansari, Shahid', '11 RATINGS', '4.5', 'Rousselet, Robin (rob)', '9 RATINGS', '2.4', 'Lucero, Terrence', '8 RATINGS', '1.0', 'Perez, Marlene', '7 RATINGS', '1.3', 'Crespo, Patricia', '7 RATINGS', '4.8', 'Knight, Ridgeway', '7 RATINGS', '2.5', 'Julius, Ed', '6 RATINGS', '2.9', 'Reinstein, Todd', '6 RATINGS']
grouped_data = [d[i:i+3] for i in range(0, len(d), 3)]
results = [professor(float(a), b, int(re.findall('^\d+', c)[0])) for a, b, c in grouped_data]

输出：

[professor(rating=3.8, name='Weiss, Earl', ratings=139), professor(rating=2.3, name='Jeppson, Catherine', ratings=114), professor(rating=3.3, name='Kiani-Aslani, Rajabali', ratings=88), professor(rating=2.6, name='Lundblad, Heidemarie', ratings=82), professor(rating=2.4, name='Stone, Ronald', ratings=75), professor(rating=3.7, name='Vedd, Rishma', ratings=66), professor(rating=3.3, name='Foster, Robert', ratings=60), professor(rating=4.9, name='Basmadzhyan, Babken', ratings=59), professor(rating=4.3, name='Grodsky, Marilyn', ratings=57), professor(rating=2.4, name='Dorsey, Norris', ratings=53), professor(rating=2.6, name='Zvinakis, Kristina', ratings=51), professor(rating=3.2, name='MacKlin, James', ratings=50), professor(rating=2.8, name='Liu, David', ratings=48), professor(rating=3.2, name='Doron, Michael', ratings=48), professor(rating=2.1, name='Rogoff, Donald', ratings=45), professor(rating=3.1, name='Sangeladji, Mohammad', ratings=43), professor(rating=4.0, name='Fountaine, Howard', ratings=42), professor(rating=4.6, name='Stout, Gary', ratings=41), professor(rating=3.4, name='Gray, Glen', ratings=34), professor(rating=3.0, name='Wilson, Barbara', ratings=31), professor(rating=4.0, name='Yoon, Sung-Wook', ratings=31), professor(rating=4.5, name='Her, Young-Won', ratings=31), professor(rating=3.0, name='Kiddoo, Robert', ratings=30), professor(rating=3.0, name='Chiu, J', ratings=27), professor(rating=3.3, name='Barker, Robert', ratings=25), professor(rating=3.7, name='Qureshi, Mahmood', ratings=23), professor(rating=3.7, name='Primes, David', ratings=22), professor(rating=2.6, name='Chen, Raymond', ratings=20), professor(rating=3.3, name='Jones, Christopher', ratings=20), professor(rating=3.2, name='Zhan, Jun', ratings=20), professor(rating=4.6, name='Bell, Janice', ratings=15), professor(rating=3.8, name='Alhashim, Dhia D', ratings=12), professor(rating=2.9, name='Ansari, Shahid', ratings=11), professor(rating=4.5, name='Rousselet, Robin (rob)', ratings=9), professor(rating=2.4, name='Lucero, Terrence', ratings=8), professor(rating=1.0, name='Perez, Marlene', ratings=7), professor(rating=1.3, name='Crespo, Patricia', ratings=7), professor(rating=4.8, name='Knight, Ridgeway', ratings=7), professor(rating=2.5, name='Julius, Ed', ratings=6), professor(rating=2.9, name='Reinstein, Todd', ratings=6)]

Answer 3

您可以使用列表切片以更少的代码实现您想要的。你知道吗

pro_rating        = temp1[0::3]
pro_name          = temp1[1::3]
pro_amount_rating = temp1[2::3]

这会将第一个元素排序为评级，第二个元素排序为名称，第三个元素排序为金额，每三个元素重复一次。你知道吗