我的forloop有问题，收到以下消息：KeyError:2

Question

我得到以下错误：Stats PlayerList=competitionList[j]KeyError:2 我在competitionList中保存了许多列表，这是一本字典。我想遍历字典中列表中的所有对象。你知道吗

def Stats(competitionList, playerList):
        no_of_competitions = int(len(competitionList))
        x = (len(playerList))
        for i in range(no_of_competitions):
            for j in range (int(x)):
            #My error occurs here
                PlayerList=competitionList[j]
                for player in PlayerList: 
                    print("player: ", player.name)
                    print ("list :", player.name, player.victories)

Answer 1

使用j访问competitionList。但是j指x，x是playerList的长度。playerList和competitionList在长度上可以延迟，所以这就是为什么会出现这种类型的错误。你知道吗

Answer 2

错误只是在这行中指出：

PlayerList=competitionList[j]

字典competitionList不包含range(x)中的一个键，在本例中是键2。确保：

1. 范围中的所有值都存在于competitionList
2. 或者只迭代字典中实际存在的值

对于第二种选择，这应该简化事情并使其工作：

for players in competitionList.values():
    for player in players:
        print("player: ", player.name)
        print ("list : ", player.name, player.victories)