我有一个元组列表，并且想要创建一个只有元组中一个字符串的一个实例的列表

Question

我有一个元组列表：

[(1, 'Twilight Sparkle', 2, 'Fluttershy'), (1, 'Twilight Sparkle', 3,
'Applejack'), (1, 'Twilight Sparkle', 4, 'Pinkie Pie'), (1, 'Twilight
Sparkle', 5, 'Rarity'), (1, 'Twilight Sparkle', 6, 'Rainbow Dash'),
(1, 'Twilight Sparkle', 7, 'Princess Celestia'), (1, 'Twilight
Sparkle', 8, 'Princess Luna'), (2, 'Fluttershy', 3, 'Applejack'), (2,
'Fluttershy', 4, 'Pinkie Pie'), (2, 'Fluttershy', 5, 'Rarity'), (2,
'Fluttershy', 6, 'Rainbow Dash'), (2, 'Fluttershy', 7, 'Princess
Celestia'), (2, 'Fluttershy', 8, 'Princess Luna'), (3, 'Applejack', 4,
'Pinkie Pie'), (3, 'Applejack', 5, 'Rarity'), (3, 'Applejack', 6,
'Rainbow Dash'), (3, 'Applejack', 7, 'Princess Celestia'), (3,
'Applejack', 8, 'Princess Luna'), (4, 'Pinkie Pie', 5, 'Rarity'), (4,
'Pinkie Pie', 6, 'Rainbow Dash'), (4, 'Pinkie Pie', 7, 'Princess
Celestia'), (4, 'Pinkie Pie', 8, 'Princess Luna'), (5, 'Rarity', 6,
'Rainbow Dash'), (5, 'Rarity', 7, 'Princess Celestia'), (5, 'Rarity',
8, 'Princess Luna'), (6, 'Rainbow Dash', 7, 'Princess Celestia'), (6,
'Rainbow Dash', 8, 'Princess Luna'), (7, 'Princess Celestia', 8,
'Princess Luna')]

我想从中创建一个只在字符串第一次出现时才出现的列表，在本例中，我希望列表是：

[(1, 'Twilight Sparkle', 2, 'Fluttershy'), (3, 'Applejack', 4, 'Pinkie
Pie'),(5, 'Rarity', 6, 'Rainbow Dash'), (7, 'Princess Celestia', 8,
'Princess Luna')]

Answer 1

您可以保留已经使用过的元素的set。你知道吗

仅当以前未使用任何元素时，才向结果添加元组：

data = [(1, 'Twilight Sparkle', 2, 'Fluttershy'), (1, 'Twilight Sparkle', 3, 'Applejack'), (1, 'Twilight Sparkle', 4, 'Pinkie Pie'), (1, 'Twilight Sparkle', 5, 'Rarity'), (1, 'Twilight Sparkle', 6, 'Rainbow Dash'), (1, 'Twilight Sparkle', 7, 'Princess Celestia'), (1, 'Twilight Sparkle', 8, 'Princess Luna'), (2, 'Fluttershy', 3, 'Applejack'), (2, 'Fluttershy', 4, 'Pinkie Pie'), (2, 'Fluttershy', 5, 'Rarity'), (2, 'Fluttershy', 6, 'Rainbow Dash'), (2, 'Fluttershy', 7, 'Princess Celestia'), (2, 'Fluttershy', 8, 'Princess Luna'), (3, 'Applejack', 4, 'Pinkie Pie'), (3, 'Applejack', 5, 'Rarity'), (3, 'Applejack', 6, 'Rainbow Dash'), (3, 'Applejack', 7, 'Princess Celestia'), (3, 'Applejack', 8, 'Princess Luna'), (4, 'Pinkie Pie', 5, 'Rarity'), (4, 'Pinkie Pie', 6, 'Rainbow Dash'), (4, 'Pinkie Pie', 7, 'Princess Celestia'), (4, 'Pinkie Pie', 8, 'Princess Luna'), (5, 'Rarity', 6, 'Rainbow Dash'), (5, 'Rarity', 7, 'Princess Celestia'), (5, 'Rarity', 8, 'Princess Luna'), (6, 'Rainbow Dash', 7, 'Princess Celestia'), (6, 'Rainbow Dash', 8, 'Princess Luna'), (7, 'Princess Celestia', 8, 'Princess Luna')]

already_added = set()
result = []

for quad in data:
    if not any((x in already_added) for x in quad):
        for x in quad:
            already_added.add(x)
        result.append(quad)

print(result)
# [(1, 'Twilight Sparkle', 2, 'Fluttershy'), (3, 'Applejack', 4, 'Pinkie Pie'), (5, 'Rarity', 6, 'Rainbow Dash'), (7, 'Princess Celestia', 8, 'Princess Luna')]

请注意，此代码对应于所需的输出，而不是问题中的描述。这种期望的输出限制更大，如果总是有耦合到已经看到的元素，则一些元素根本不会被添加。用于：

data = [(1, 'a', 2, 'b'), (1, 'a', 3, 'c'), (2, 'b', 4, 'd')]

输出为：

[(1, 'a', 2, 'b')]

看不到3、4、c或d！你知道吗