我想四舍五入的4列有小数位的值高达4位小数位在一个csv fi

Question

我的意见是

status,avgMeasuredTime,avgSpeed,extID,medianMeasuredTime,TIMESTAMP,vehicleCount,_id,REPORT_ID,Lat1,Long1,Lat2,Long2,Distance between 2 points,duration of measurements,ndt in kmh
OK,74,50,668,74,1406859600,5,20746220,158324,56.23172069428216,10.104986076057457,56.23172069428216,56.22579478256016,1030,52,71
OK,926,4,981,926,1412098500,0,28060227,210173,56.20913963031665,10.246642527612721,56.20913963031665,56.2026461982616,1106,88,45

预期产量：

status,avgMeasuredTime,avgSpeed,extID,medianMeasuredTime,TIMESTAMP,vehicleCount,_id,REPORT_ID,Lat1,Long1,Lat2,Long2,Distance between 2 points,duration of measurements,ndt in kmh
OK,74,50,668,74,1406859600,5,20746220,158324,56.2317,10.1050,56.2317,56.2258,1030,52,71
OK,926,4,981,926,1412098500,0,28060227,210173,56.2091,10.2466,56.2091,56.2026,1106,88,45

如你所见，我想把第10、11、12、13栏四舍五入。你知道吗

请帮忙。提前谢谢。你知道吗

Answer 1

awk方法：

awk 'BEGIN{FS=OFS=","}NR>1{for(i=NF-3;i>NF-7;i ) $i=sprintf("%.4f",$i)}1' file

输出：

status,avgMeasuredTime,avgSpeed,extID,medianMeasuredTime,TIMESTAMP,vehicleCount,_id,REPORT_ID,Lat1,Long1,Lat2,Long2,Distance between 2 points,duration of measurements,ndt in kmh
OK,74,50,668,74,1406859600,5,20746220,158324,56.2317,10.1050,56.2317,56.2258,1030,52,71
OK,926,4,981,926,1412098500,0,28060227,210173,56.2091,10.2466,56.2091,56.2026,1106,88,45

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for(i=NF-3;i>NF-7;i )-从末尾的第4个字段开始遍历4个字段

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注：如果列数始终是静态的，您可以通过它们的位置号直接访问它们：

awk 'BEGIN{FS=OFS=","}NR>1{for(i=10;i<=13;i++) $i=sprintf("%.4f",$i)}1' file

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如果您想要Python方法-我们开始：

with open("yourfile", 'r') as f:
    for k,l in enumerate(f.read().splitlines()):
        if k > 0:
            items = l.split(',')
            items[-4:-8:-1] = ["%.4f" % float(i) for i in items[-4:-8:-1]]
            l = ','.join(items)
        print(l)

输出相同