head = {
"type":"FeatureCollection",
"features":[
{
"type":"Feature",
"id":4,
"geometry":{
"type":"Point",
"coordinates":[
-0.1044968729335983,
51.52014078866054
]
},
"properties":{
"description":"Фаррингдон-стрит",
"iconCaption":"Фаррингдон-стрит",
"marker-color":"#b51eff"
}
}
]
}
我在列表中的第一项总是这个(下面)
head['features'][0]['geometry']['coordinates'][0] = long
head['features'][0]['geometry']['coordinates'][1] = lat
zone = {
"type":"Feature",
"id":0,
"geometry":{
"type":"Polygon",
"coordinates":[]
},
"properties":{
"description":"Вокзал Паддингтон",
"fill":"#ff931e",
"fill-opacity":0.3,
"stroke":"#e6761b",
"stroke-width":"2",
"stroke-opacity":0.9
}
}
所以这是我的密码。它识别出我需要的地址的数量,并将那么多的条目添加到列表中
for i in range (0, len(lst)):
head['features'].append(zone)
不知何故,我得到了坐标并将其存储在列表lst[]中。当我试图用代码替换它时:
for k in range (0, (len (lst)) ):
head['features'][k+1]['geometry']['coordinates'] = lst[k]['data-points']
它用列表lst[]中的最后一项替换“coordinate”中的所有项。 奇怪的问题。但当我在pythonshell中手动执行时,它就可以工作了。你知道吗
目前没有回答
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