我完全被难住了。我用标签围绕问题的关键。非常感谢您的帮助!你知道吗
import pygame
import time
import random
pygame.init()
display_width = 600
display_height = 600
display = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('Snake')
clock = pygame.time.Clock()
fps = 10
white = (255, 255, 255)
red = (200, 0, 0)
green = (0, 200, 0)
blue = (0, 0, 200)
black = (0, 0, 0)
def extend_snake(snake):
x = snake[len(snake) - 1][0]
y = snake[len(snake) - 1][1]
## for i in snake:
## print(i)
return ([x, y])
def spawn_fruit():
x = random.randrange(fruit_rad, display_width - fruit_rad, 2 * fruit_rad)
y = random.randrange(fruit_rad, display_height - fruit_rad, 2 * fruit_rad)
return ((x, y))
def pause():
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_p:
return
score = 0
snake = []
snake_size = 10
snake.append([display_width / 2, display_height / 2])
snake_dx = 0
snake_dy = 0
fruit = []
fruit_count = 5
fruit_rad = 5
for a in range(fruit_count):
fruit.append(spawn_fruit())
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_p:
pause()
elif event.key == pygame.K_a or event.key == pygame.K_LEFT:
snake_dx = -snake_size
snake_dy = 0
elif event.key == pygame.K_d or event.key == pygame.K_RIGHT:
snake_dx = snake_size
snake_dy = 0
elif event.key == pygame.K_w or event.key == pygame.K_UP:
snake_dy = -snake_size
snake_dx = 0
elif event.key == pygame.K_s or event.key == pygame.K_DOWN:
snake_dy = snake_size
snake_dx = 0
print(snake)
for coord in fruit:
if snake[0][0] + fruit_rad == coord[0] and snake[0][1] + fruit_rad == coord[1]:
fruit.remove(coord)
fruit.append(spawn_fruit())
snake.append(extend_snake(snake))
score += 1
fps += 1
for i in range(len(snake) - 1, 0, -1):
snake[i] = snake[i - 1]
################################################
try:
print('1', snake[1])
except:
pass
snake[0][0] += snake_dx
snake[0][1] += snake_dy
try:
print('2', snake[1])
except:
pass
#########################################################
display.fill(white)
for coord in fruit:
pygame.draw.circle(display, red, coord, fruit_rad)
for coord in snake:
pygame.draw.rect(display, black, [coord[0], coord[1], snake_size, snake_size])
pygame.display.update()
clock.tick(fps)
这将返回例如:
1(100,100)
2(110,100)
无论我在哪里打印(snake),其中的每个列表都是相同的。 有人能解释一下为什么会发生这种情况,以及我能做些什么来防止它吗?你知道吗
当您执行-
snake[i] = snake[i - 1]
时,您只是将snake[i - 1]
的引用传递给snake[i]
。这似乎发生在所有人身上然后,当您在
snake[i]
内的任何地方进行任何更改时,实际上您正在对引用的对象进行更改,因此这些更改也反映在所有其他snake[i]
中。你知道吗要使逻辑正常工作,需要使用
copy.deepcopy
来创建对象的深度副本,这样更改就不会反映在其他snake[i]
中在你的情况下你需要做-
示例-
设置snake[i]=snake[i-1]使它们成为同一个对象,从而解释了为什么它们都被编辑,即使代码只编辑了其中一个。你知道吗
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