我如何确定整数是2的倍数而不是3的倍数打印“<myint>仅是2的倍数”呢？使用python

Answer 1

做什么呢

your_number%2 == 0 and your_number%3 != 0

其中%是模运算符，用左手操作数除以右手操作数并返回余数。因此，如果余数等于0，则左操作数是右操作数的倍数。你知道吗

因此

your_number%2 == 0如果your_number是2的倍数，则返回True

以及

如果your_number不是3的倍数，则your_number%3 != 0返回True。你知道吗

为了给您提供完整的答案，您需要：

if myint%2 == 0 and myintr%3 != 0:
    print(str(myint), "is a multiple of 2 and not a multiple of 3")

Answer 2

你可以这样做：

#first checks if myint / 2 doesn't has a reminder
#then checks if myint / 3 has a reminder
if not myint % 2 and myint % 3: 
    print(myint,"is a multiple of 2 only")

或者如果你想：

if myint % 2 == 0 and myint % 3 != 0: 
    print(myint,"is a multiple of 2 only")

两者工作原理相同