多用户输入打印特定的数据

Question

我现在只想输入多组要单独计算的整数。 它会像这样流动。你知道吗

首先一次获取所有用户输入。你知道吗

输入数字1。。。2、4、23、45、57

输入数字2。。。9、23、45、47、33

输入数字3。。。2,41,23,45,55岁

然后输出一次全部打印出来。你知道吗

数字1的序列。。。2,0,1,0,1,1

数字2的序列。。。1,0,1,1,2,0

数字3的顺序。。。1,0,1,0,2,1

这是我的密码。你知道吗

import collections 

the_input1 = raw_input("Enter numbers 1... ")
the_input2 = raw_input("Enter numbers 2... ")
the_input3 = raw_input("Enter numbers 3... ")

the_list1 = [int(x) for x in the_input1.strip("[]").split(",")]
the_list2 = [int(x) for x in the_input2.strip("[]").split(",")]
the_list3 = [int(x) for x in the_input3.strip("[]").split(",")]

group_counter = collections.Counter(x//10 for x in the_list1)
group_counter = collections.Counter(x//10 for x in the_list2)
group_counter = collections.Counter(x//10 for x in the_list3)

bin_range = range (6) 

for bin_tens in bin_range: 
    print "There were {} in {} to {}".format(group_counter[bin_tens], bin_tens*10, bin_tens*10+9)

如有任何回应，我们将不胜感激。。谢谢您。。你知道吗

Answer 1

如果我理解正确的话，你需要的频率范围0-9，10-19，…，50-59分别为你的3个输入。我重构了您的程序以实现以下目标：

import collections 

the_inputs = []
for i in range(3):
    the_inputs.append(raw_input("Enter numbers {}... ".format(i+1)))

the_lists = []
for the_input in the_inputs:
    the_lists.append([int(x)//10 for x in the_input.strip("[]").split(",")])

for i, the_list in enumerate(the_lists):
    print "Input {}".format(i+1)
    group_counter = collections.Counter(the_list)
    bin_range = range (6) 
    for bin_tens in bin_range: 
        print "There were {} in {} to {}".format(group_counter[bin_tens], bin_tens*10, bin_tens*10+9)

我用你给定的输入得到了预期的输出。你知道吗