从元素列表中提取匹配的编号

Question

我有一个混合了数字、字母和特殊字符的元素列表。你知道吗

string = ['1 B, 14/A - P,1C,2A,21 C - A','3P,21B,2-A,1A','3C,2-W,ABC 200','3 Z,ABC 100 - BB','ABC 300,ABC 200','ABC 200,ABC 100','1c/A,2 - z']
string

['1 B, 14/A - P,1C,2A,21 C - A',    
 '3P,21B,2-A,1A',
 '3C,2-W,ABC 200',
 '3 Z,ABC 100 - BB',
 'ABC 300,ABC 200',
 'ABC 200,ABC 100',
 '1c/A,2 - z']

我想提取符合条件的元素。你知道吗

条件：-列表中的元素应为starting with the Matching number或

从ABC (Matching number)开始

所需输出：

starting_with_one = ['1 B, 14/A - P,1C,2A,21 C - A','3P,21B,2-A,1A','3 Z,ABC 100 - BB','ABC 200,ABC 100','1c/A,2 - z']

['1 B, 14/A - P,1C,2A,21 C - A',  --->    # Here `1 B ,14/A - P,1C` are contains the number 1  
 '3P,21B,2-A,1A',                --->   # Here `1A` Contains the number 1   
 '3 Z,ABC 100 - BB',               --->  # Here `ABC 100 - BB` Contains the number 1  
 'ABC 200,ABC 100',                   --->  # Here `ABC 100` Contains the number 1
 '1c/A,2 - z']                        ---> Here `1c/A' contains 1



starting_with_two = ['1 B, 14/A - P,1C,2A,21 C - A','3P,21B,2-A,1A','3C,2-W,ABC 200','ABC 300,ABC 200','ABC 200,ABC 100','1c/A,2 - z']

['1 B, 14/A - P,1C,2A,21 C - A',
 '3P,21B,2-A,1A',
 '3C,2-W,ABC 200',
 'ABC 300,ABC 200',
 'ABC 200,ABC 100',
 '1c/A,2 - z']

我尝试的是：

搜索数字1

for i in string:
    print(re.search(r"(^|[^\d])(1)", i))

<_sre.SRE_Match object; span=(0, 1), match='1'>
<_sre.SRE_Match object; span=(10, 12), match=',1'>
None
<_sre.SRE_Match object; span=(7, 9), match=' 1'>
None
<_sre.SRE_Match object; span=(11, 13), match=' 1'>
<_sre.SRE_Match object; span=(0, 1), match='1'>

Answer 1

你可以用

r'\b(?:ABC\s+)?1'

确定要保留的字符串。见the regex demo。你知道吗

细节

• \b-单词边界
• (?:ABC\s+)?-可选子字符串：ABC，然后是1+空格
• 1-1字符。你知道吗

见Python demo：

import re
strs = ['1 B, 14/A - P,1C,2A,21 C - A','3P,21B,2-A,1A','3C,2-W,ABC 200','3 Z,ABC 100 - BB','ABC 300,ABC 200','ABC 200,ABC 100','1c/A,2 - z']
for s in strs:
    if re.search(r'\b(?:ABC\s+)?1', s):
        print(s)

输出：

1 B, 14/A - P,1C,2A,21 C - A
3P,21B,2-A,1A
3 Z,ABC 100 - BB
ABC 200,ABC 100
1c/A,2 - z