试着写一个程序来显示多达40小时的正常时间和任何超过这个时间的加班时间。你知道吗
当前获取的输出接受超过40的输入并打印输入-1作为常规时间,1作为超时时间。似乎不知道我哪里出错了。你知道吗
def data():
wage = float(input('What is your payrate? '))
while wage < 7 or wage > 50:
print('Invalid input. Wage must be between $7.00 and $51.00. Please try again.')
rate = float(input('What is your payrate? '))
hours = float(input('How many hours were worked? '))
while hours < 8 or hours > 86:
print('Invalid input. Hours worked must be between 8 and 86. Please try again.')
hours = float(input('How many hours were worked? '))
return hours, wage
def timeCalc(hours):
if hours <= 40:
return[hours, False]
else:
othour = hours - 40
return[othour, True]
def payCalc(hours, wage):
if hours[1]:
othours = hours[1]
otpay = othours * (wage * 1.5)
regularpay = 40 * wage
return otpay, regularpay, othours
else:
return None
def main():
hours, wage = data()
if payCalc(timeCalc(hours), wage) == None:
print(' Payroll Information ')
print('Pay Rate: $%.2f' % wage)
print('Regular Hours: %.0f' % hours)
print('Overtime Hours: 0')
print('Regular pay: $%.2f' % (hours * wage))
print('Overtime pay: $0.00')
print('')
print('Total pay: $%.2f' % (hours * wage))
else:
otpay, regularpay, othours = payCalc(timeCalc(hours), wage,)
print(' Payroll Information ')
print('Pay Rate: $%.2f' % wage)
print('Regular Hours: %.0f' % (hours - othours))
print('Overtime Hours: %.0f' % othours)
print('Regular pay: $%.2f' % (hours * wage))
print('Overtime pay: $%.2f' % otpay)
print('Total pay: $%.2f' % (regularpay + otpay))
main()
输出看起来是这样的(为了清晰起见,我添加了空格):
What is your payrate? 11.5
How many hours were worked? 48
Payroll Information
Pay Rate: $11.50
Regular Hours: 47
Overtime Hours: 1
Regular pay: $552.00
Overtime pay: $17.25
Total pay: $477.25
感谢您的帮助
在payCalc函数中,您需要编写
othours = hours[0]
而不是othours = hours[1]
来获得小时数(因为现在它给出了数字的真值或假值)这是输出
希望这能奏效!!你知道吗
payCalc函数,将if hours[1]更改为if hours[0]
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