使用Python打印到CSV文件

2024-06-16 15:00:11 发布

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我需要打印头和数据行到一个CSV文件。这是我的密码:

import csv

import sys

  with open(r'C:\Users\testuser\Desktop\raw_inpuy.csv','rb') as csvfile:

        reader=csv.reader(csvfile,delimiter=',')
        first=True
        data={}
        for row in reader:
            if first:
                 first= False
                   continue
            if not int(row[1]) in data:
                 data[int(row[1])]=[]
               data[int(row[1])].append(float(row[3]))


    with open (r'C:\Users\testuser\Desktop\outcome.csv','wb') as f_out:
        outwriter=csv.writer(f_out,delimiter=',')
       f_out.write(";".join(['Size','S1','S2','S3','S4']))
       for item in data:
        row=[item]
        row.extend(data[item])
        f_out.write(";".join(map(str,row)))

我得到这个错误:

**ERROR Expected a character buffer obj**

Tags: csvinimportdatawithopenoutitem
2条回答

应该用str而不是list来填充writer.write

 writer.write(";".join(['Size','S1','S2','S3','S4']))

此外:

 writer.write(";".join(map(str, row)))

与其尝试构建自己的CSV记录,不如让csv模块来处理它。像这样:

import csv

data = [[10, 'foo', 'bar', 'blue', 'green'],
        [20, 'bar', 'foo', 'blue', 'green'],
        [30, 'ba', 'bar', 'red', 'white']]

with open (r'C:\Users\testuser\Desktop\outcome.csv','w') as file:
  writer = csv.writer(file)
  writer.writerow(['Size','S1','S2','S3','S4'])
  for row in data:
    writer.writerow(row)

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