如何在另一个while循环中使用if else语句

Question

我是新来的编码。我想试着写一个简单的石头剪刀布游戏。但我不知道怎么结束比赛。你知道吗

在这个程序的末尾，如果用户输入错误，我想再次转到end变量。我试着用注释行，但它不工作。你知道吗

player1 = input("What is player 1's name ? ")
player2 = input("What is player 2's name ? ")

player1 = player1.title()
player2 = player2.title()
while True:
    print(player1 + " What do you choose ? rock / paper / scissors : ")
    a = input()

    print(player2 + " What do you choose ? rock / paper / scissors : ")
    b = input()
    if a == "rock" and b == "scissors" :
        print(player1, "won !!!")
    elif a == "scissors" and b == "rock":
        print(player2, "won !!!")

    elif a == "paper" and b == "rock":
        print(player1, "won !!!")
    elif a == "rock" and b == "paper":
        print(player2, "won !!!")

    elif a == "scissors" and b == "paper":
        print(player1, "won !!!")
    elif a == "paper" and b == "scissors":
        print(player2, "won !!!")

    elif a == b:
        print("Its a tie :-(")

    elif a or b != "rock" or "paper" or "scissors":

        print("Wrong input, Try again")
    end = input("Do you want to play again ? yes/no ") == "yes"
    if input == "yes":
        continue
    else:

        print('''

        GAME OVER''')
        break
#    elif input != "yes" or "no":
#        print("Wrong input, Try again. yes or no ?")

我希望它结束游戏，如果输入是“否”和重新启动游戏，如果输入是“是”如果输入不正确，我希望提示再次出现。你知道吗

Answer 1

只需检查end的值

if end is True:
    continue
else:
    break

因为，通过将input（）与“yes”进行比较，您已经将end的值设置为布尔值，它将说明用户是否想要结束游戏？ 另外，您没有初始化输入变量，最后一个elif条件将始终为true，如注释中所述。你知道吗