我正在开发一个算法,信号将通过python发送到Firebase。流量是当我按下按钮时,它会被检测到,并在释放时计数为1次。你知道吗
我尝试的python代码是这样的
AS = serial.Serial('COM8',9600)
url = 'https://xxx.firebaseio.com/'
AoS = 40
FB = firebase.FirebaseApplication(url, None)
result = FB.patch('/ParkingSeat/',{'Amount of the seats': str(AoS) + '/40'})
while (1==1):
if(AS.inWaiting()>0):
msg = AS.readline().strip().decode()
if (msg == '1'):
print ("Waiting for release")
print (msg)
if (AoS>0) and (msg == '0'):
AoS-=1
print ("The Signal now is " + str(AoS))
result = FB.patch('/ParkingSeat/',{'Amount of the seats': str(AoS) + '/40'})
if (msg == '2'):
print ("Waiting for release")
print (msg)
if (AoS<40) and (msg == '0'):
AoS+=1
print ("The Signal now is " + str(AoS))
result = FB.patch('/ParkingSeat/',{'Amount of the seats': str(AoS) + '/40'})
print(msg)
我尝试的arduino代码是这样的
const int BUTTON1 = 6;
const int BUTTON2 = 7;
String i, j, x;
int ButtonState = 0;
void setup() {
// put your setup code here, to run once:
Serial.begin(9600);
pinMode(BUTTON1, INPUT_PULLUP);
pinMode(BUTTON2, INPUT_PULLUP);
}
void loop() {
if (digitalRead(BUTTON1) == LOW) {
delay(500);
i = "1";
Serial.println(i);
}
else if (digitalRead(BUTTON2) == LOW) {
delay(500);
j = "2";
Serial.println(j);
}
else {
delay(500);
x = "0";
Serial.println(x);
}
}
我也在连接python和arduino。arduino一直在向python发送信号0。当按下按钮1或按钮2时,它将发送1或2。你知道吗
所以,我正在尝试的代码是用户按下按钮1或按钮2给出的输出是1,结果将在用户立即释放按钮后发送。你知道吗
但现在我的代码只能在按下按钮1或按钮2时接收信号。当我一直按这个按钮时,它会一直发出信号,但我不想。我怎样才能写出一次松开按钮后发出的信号?你知道吗
目前没有回答
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