在Django中将图像保存为临时文件
我刚接触Python和Django,最近用Django开发了一个项目。在这个项目里,所有的图片都有水印。我用下面的代码给所有图片加了水印……
from PIL import Image
def image_watermark(request,image_id):
photo = Photo.objects.get(pk=image_id)
watermark = Image.open('{0}/{1}'.format(settings.MEDIA_ROOT,'wmark.png'))
img = Image.open(photo.photo.file)
img.paste(watermark,(img.size[0]-watermark.size[0],img.size[1]- watermark.size[1]),watermark)
img.save('{0}/{1}'.format(settings.MEDIA_ROOT,photo.photo.name), quality=80)
wrapper = FileWrapper(open(photo.photo.url, 'rb'))
response = StreamingHttpResponse(wrapper, 'image/jpeg')
response['Content-Length'] = os.path.getsize(photo.photo.url)
response['Content-Disposition'] = 'attachment; filename=photo.jpg'
return response
现在我所有的图片都有水印了。但问题是,作为用户,如果我下载这些图片,我发现下载下来的图片也是有水印的。我想下载的是没有水印的原图,应该怎么解决这个问题呢?
1 个回答
5
你需要把带水印的图片存储到一个不同的文件里。首先,你需要创建一个新的列来存放带水印的图片。
class Photo(models.Model):
...
watermarked_photo = ImageField()
然后,当你把带水印的图片保存到那个列里时。
from PIL import Image
def image_watermark(request,image_id):
photo = Photo.objects.get(pk=image_id)
# Only need to watermark when there's no watermark
if not photo.watermarked_photo.name:
photo.watermarked_photo.name = 'watermarked_' + photo.photo.name
watermark = Image.open('{0}/{1}'.format(settings.MEDIA_ROOT,'wmark.png'))
img = Image.open(photo.photo.file)
img.paste(watermark,(img.size[0]-watermark.size[0],img.size[1]- watermark.size[1]),watermark)
img.save('{0}/{1}'.format(settings.MEDIA_ROOT, photo.watermarked_photo.name), quality=80)
photo.save()
wrapper = FileWrapper(open(photo.watermarked_photo.url, 'rb'))
response = StreamingHttpResponse(wrapper, 'image/jpeg')
response['Content-Disposition'] = 'attachment; filename=photo.jpg'
return response
我的Django技能有点生疏,所以这段代码可能需要一些修改才能正常工作。不过这个思路应该是没问题的。
如果你只想使用一个临时文件,那就试试这个。
from PIL import Image
import tempfile
def image_watermark(request,image_id):
photo = Photo.objects.get(pk=image_id)
watermark = Image.open('{0}/{1}'.format(settings.MEDIA_ROOT,'wmark.png'))
img = Image.open(photo.photo.file)
img.paste(watermark,(img.size[0]-watermark.size[0],img.size[1]- watermark.size[1]),watermark)
tmpfile = tempfile.TemporaryFile()
img.save(tmpfile, img.format, quality=80)
tmpfile.seek(0)
wrapper = FileWrapper(tmpfile)
response = StreamingHttpResponse(wrapper, 'image/jpeg')
response['Content-Disposition'] = 'attachment; filename=photo.jpg'
return response