Matplotlib RegularPolygon集合在画布上的位置
我正在尝试用Python绘制一个特征图（自组织映射，简称SOM）。为了简单起见，可以想象成一个二维图，每个单元用六边形表示。
正如这个话题所展示的：Python中的六边形自组织映射，这些六边形是并排放置的，形成一个网格。
我写了以下这段代码，它在处理固定数量的多边形和少量形状（比如6 x 6或10 x 4的六边形）时运行得很好。不过，这种方法的一个重要特点是应该支持从3 x 3开始的任何网格形状。
def plot_map(grid,
d_matrix,
w=10,
title='SOM Hit map'):
"""
Plot hexagon map where each neuron is represented by a hexagon. The hexagon
color is given by the distance between the neurons (D-Matrix) Scaled
hexagons will appear on top of the background image whether the hits array
is provided. They are scaled according to the number of hits on each
neuron.
Args:
- grid: Grid dictionary (keys: centers, x, y ),
- d_matrix: array contaning the distances between each neuron
- w: width of the map in inches
- title: map title
Returns the Matplotlib SubAxis instance
"""
n_centers = grid['centers']
x, y = grid['x'], grid['y']
fig = plt.figure(figsize=(1.05 * w, 0.85 * y * w / x), dpi=100)
ax = fig.add_subplot(111)
ax.axis('equal')
# Discover difference between centers
collection_bg = RegularPolyCollection(
numsides=6, # a hexagon
rotation=0,
sizes=(y * (1.3 * 2 * math.pi * w) ** 2 / x,),
edgecolors = (0, 0, 0, 1),
array= d_matrix,
cmap = cm.gray,
offsets = n_centers,
transOffset = ax.transData,
)
ax.add_collection(collection_bg, autolim=True)
ax.axis('off')
ax.autoscale_view()
ax.set_title(title)
divider = make_axes_locatable(ax)
cax = divider.append_axes("right", size="5%", pad=0.05)
plt.colorbar(collection_bg, cax=cax)
return ax
我尝试做一些可以自动识别网格形状的东西，但没有成功（我也不太确定为什么）。六边形之间总是会出现不想要的空隙。
总结一下：我希望能生成3x3、6x6或10x4（等等）这样的网格，使用六边形并且在给定点之间没有空隙，同时设置绘图的宽度。
根据要求，这里是六边形位置的数据。可以看到，它总是相同的模式。
3x3
{'centers': array([[ 1.5 , 0.8660254 ],
[ 2.5 , 0.8660254 ],
[ 3.5 , 0.8660254 ],
[ 1. , 1.73205081],
[ 2. , 1.73205081],
[ 3. , 1.73205081],
[ 1.5 , 2.59807621],
[ 2.5 , 2.59807621],
[ 3.5 , 2.59807621]]),
'x': array([ 3.]),
'y': array([ 3.])}
6x6
{'centers': array([[ 1.5 , 0.8660254 ],
[ 2.5 , 0.8660254 ],
[ 3.5 , 0.8660254 ],
[ 4.5 , 0.8660254 ],
[ 5.5 , 0.8660254 ],
[ 6.5 , 0.8660254 ],
[ 1. , 1.73205081],
[ 2. , 1.73205081],
[ 3. , 1.73205081],
[ 4. , 1.73205081],
[ 5. , 1.73205081],
[ 6. , 1.73205081],
[ 1.5 , 2.59807621],
[ 2.5 , 2.59807621],
[ 3.5 , 2.59807621],
[ 4.5 , 2.59807621],
[ 5.5 , 2.59807621],
[ 6.5 , 2.59807621],
[ 1. , 3.46410162],
[ 2. , 3.46410162],
[ 3. , 3.46410162],
[ 4. , 3.46410162],
[ 5. , 3.46410162],
[ 6. , 3.46410162],
[ 1.5 , 4.33012702],
[ 2.5 , 4.33012702],
[ 3.5 , 4.33012702],
[ 4.5 , 4.33012702],
[ 5.5 , 4.33012702],
[ 6.5 , 4.33012702],
[ 1. , 5.19615242],
[ 2. , 5.19615242],
[ 3. , 5.19615242],
[ 4. , 5.19615242],
[ 5. , 5.19615242],
[ 6. , 5.19615242]]),
'x': array([ 6.]),
'y': array([ 6.])}
11x4
{'centers': array([[ 1.5 , 0.8660254 ],
[ 2.5 , 0.8660254 ],
[ 3.5 , 0.8660254 ],
[ 4.5 , 0.8660254 ],
[ 5.5 , 0.8660254 ],
[ 6.5 , 0.8660254 ],
[ 7.5 , 0.8660254 ],
[ 8.5 , 0.8660254 ],
[ 9.5 , 0.8660254 ],
[ 10.5 , 0.8660254 ],
[ 11.5 , 0.8660254 ],
[ 1. , 1.73205081],
[ 2. , 1.73205081],
[ 3. , 1.73205081],
[ 4. , 1.73205081],
[ 5. , 1.73205081],
[ 6. , 1.73205081],
[ 7. , 1.73205081],
[ 8. , 1.73205081],
[ 9. , 1.73205081],
[ 10. , 1.73205081],
[ 11. , 1.73205081],
[ 1.5 , 2.59807621],
[ 2.5 , 2.59807621],
[ 3.5 , 2.59807621],
[ 4.5 , 2.59807621],
[ 5.5 , 2.59807621],
[ 6.5 , 2.59807621],
[ 7.5 , 2.59807621],
[ 8.5 , 2.59807621],
[ 9.5 , 2.59807621],
[ 10.5 , 2.59807621],
[ 11.5 , 2.59807621],
[ 1. , 3.46410162],
[ 2. , 3.46410162],
[ 3. , 3.46410162],
[ 4. , 3.46410162],
[ 5. , 3.46410162],
[ 6. , 3.46410162],
[ 7. , 3.46410162],
[ 8. , 3.46410162],
[ 9. , 3.46410162],
[ 10. , 3.46410162],
[ 11. , 3.46410162]]),
'x': array([ 11.]),
'y': array([ 4.])}
1 个回答
5
我找到了一种解决办法，就是根据给定的dpi（每英寸点数）来计算图形的大小（以英寸为单位）。然后，我通过画一个隐藏的散点图来计算两个相邻点之间的像素距离。这样，我就能计算出六边形的内切圆半径，并正确估算六边形内部圆的大小（这正是matplotlib所需要的）。
最后没有出现任何空隙！
import matplotlib.pyplot as plt
from matplotlib import colors, cm
from matplotlib.collections import RegularPolyCollection
from mpl_toolkits.axes_grid1 import make_axes_locatable
import math
import numpy as np
def plot_map(grid,
d_matrix,
w=1080,
dpi=72.,
title='SOM Hit map'):
"""
Plot hexagon map where each neuron is represented by a hexagon. The hexagon
color is given by the distance between the neurons (D-Matrix)
Args:
- grid: Grid dictionary (keys: centers, x, y ),
- d_matrix: array contaning the distances between each neuron
- w: width of the map in inches
- title: map title
Returns the Matplotlib SubAxis instance
"""
n_centers = grid['centers']
x, y = grid['x'], grid['y']
# Size of figure in inches
xinch = (x * w / y) / dpi
yinch = (y * w / x) / dpi
fig = plt.figure(figsize=(xinch, yinch), dpi=dpi)
ax = fig.add_subplot(111, aspect='equal')
# Get pixel size between to data points
xpoints = n_centers[:, 0]
ypoints = n_centers[:, 1]
ax.scatter(xpoints, ypoints, s=0.0, marker='s')
ax.axis([min(xpoints)-1., max(xpoints)+1.,
min(ypoints)-1., max(ypoints)+1.])
xy_pixels = ax.transData.transform(np.vstack([xpoints, ypoints]).T)
xpix, ypix = xy_pixels.T
# In matplotlib, 0,0 is the lower left corner, whereas it's usually the
# upper right for most image software, so we'll flip the y-coords
width, height = fig.canvas.get_width_height()
ypix = height - ypix
# discover radius and hexagon
apothem = .9 * (xpix[1] - xpix[0]) / math.sqrt(3)
area_inner_circle = math.pi * (apothem ** 2)
collection_bg = RegularPolyCollection(
numsides=6, # a hexagon
rotation=0,
sizes=(area_inner_circle,),
edgecolors = (0, 0, 0, 1),
array= d_matrix,
cmap = cm.gray,
offsets = n_centers,
transOffset = ax.transData,
)
ax.add_collection(collection_bg, autolim=True)
ax.axis('off')
ax.autoscale_view()
ax.set_title(title)
divider = make_axes_locatable(ax)
cax = divider.append_axes("right", size="10%", pad=0.05)
plt.colorbar(collection_bg, cax=cax)
return ax