python 3.3 字典:如何将PyDictKeysObject结构转换为Python类?
我正在尝试修改Brandon Rhodes的代码,链接在这里:检查CPython字典内部的例程,让它可以在CPython 3.3上运行。
我觉得我已经成功地翻译了这个结构。
typedef PyDictKeyEntry *(*dict_lookup_func)
(PyDictObject *mp, PyObject *key, Py_hash_t hash, PyObject ***value_addr);
struct _dictkeysobject {
Py_ssize_t dk_refcnt;
Py_ssize_t dk_size;
dict_lookup_func dk_lookup;
Py_ssize_t dk_usable;
PyDictKeyEntry dk_entries[1];
};
我认为下面的内容现在看起来不错:
from ctypes import Structure, c_ulong, POINTER, cast, py_object, CFUNCTYPE
LOOKUPFUNC = CFUNCTYPE(POINTER(PyDictKeyEntry), POINTER(PyDictObject),
py_object, c_ulong, POINTER(POINTER(py_object)))
class PyDictKeysObject(Structure):
"""A key object"""
_fields_ = [
('dk_refcnt', c_ssize_t),
('dk_size', c_ssize_t),
('dk_lookup', LOOKUPFUNC),
('dk_usable', c_ssize_t),
('dk_entries', PyDictKeyEntry * 1),
]
PyDictKeysObject._dk_entries = PyDictKeysObject.dk_entries
PyDictKeysObject.dk_entries = property(lambda s:
cast(s._dk_entries, POINTER(PyDictKeyEntry * s.dk_size))[0])
这行代码现在可以正常工作,其中 d == {0: 0, 1: 1, 2: 2, 3: 3}
:
obj = cast(id(d), POINTER(PyDictObject)).contents # works!!`
这是我从C结构 PyDictObject的翻译:
class PyDictObject(Structure): # an incomplete type
"""A dictionary object."""
def __len__(self):
"""Return the number of dictionary entry slots."""
pass
def slot_of(self, key):
"""Find and return the slot at which `key` is stored."""
pass
def slot_map(self):
"""Return a mapping of keys to their integer slot numbers."""
pass
PyDictObject._fields_ = [
('ob_refcnt', c_ssize_t),
('ob_type', c_void_p),
('ma_used', c_ssize_t),
('ma_keys', POINTER(PyDictKeysObject)),
('ma_values', POINTER(py_object)), # points to array of ptrs
]
1 个回答
3
我的问题是如何访问一个在Cpython 3.3中实现的Python字典背后的C结构。我从在 cpython/Objects/dictobject.c 和 Include/dictobject.h 中提供的C结构开始。定义字典时涉及到三个C结构:PyDictObject、PyDictKeysObject 和 PyDictKeyEntry。每个C结构正确翻译成Python的方式如下。注释部分说明了我需要修正的地方。感谢@eryksun一路上的指导!!
class PyDictKeyEntry(Structure):
"""An entry in a dictionary."""
_fields_ = [
('me_hash', c_ulong),
('me_key', py_object),
('me_value', py_object),
]
class PyDictObject(Structure):
"""A dictionary object."""
pass
LOOKUPFUNC = CFUNCTYPE(POINTER(PyDictKeyEntry), POINTER(PyDictObject), py_object, c_ulong, POINTER(POINTER(py_object)))
class PyDictKeysObject(Structure):
"""An object of key entries."""
_fields_ = [
('dk_refcnt', c_ssize_t),
('dk_size', c_ssize_t),
('dk_lookup', LOOKUPFUNC), # a function prototype per docs
('dk_usable', c_ssize_t),
('dk_entries', PyDictKeyEntry * 1), # an array of size 1; size grows as keys are inserted into dictionary; this variable-sized field was the trickiest part to translate into python
]
PyDictObject._fields_ = [
('ob_refcnt', c_ssize_t), # Py_ssize_t translates to c_ssize_t per ctypes docs
('ob_type', c_void_p), # could not find this in the docs
('ma_used', c_ssize_t),
('ma_keys', POINTER(PyDictKeysObject)),
('ma_values', POINTER(py_object)), # Py_Object* translates to py_object per ctypes docs
]
PyDictKeysObject._dk_entries = PyDictKeysObject.dk_entries
PyDictKeysObject.dk_entries = property(lambda s: cast(s._dk_entries, POINTER(PyDictKeyEntry * s.dk_size))[0]) # this line is called every time the attribute dk_entries is accessed by a PyDictKeyEntry instance; it returns an array of size dk_size starting at address _dk_entries. (POINTER creates a pointer to the entire array; the pointer is dereferenced (using [0]) to return the entire array); the code then accesses the ith element of the array)
下面这个函数可以访问Python字典背后的PyDictObject:
def dictobject(d):
"""Return the PyDictObject lying behind the Python dict `d`."""
if not isinstance(d, dict):
raise TypeError('cannot create a dictobject from %r' % (d,))
return cast(id(d), POINTER(PyDictObject)).contents
如果d是一个包含键值对的Python字典,那么obj就是包含这些键值对的PyDictObject实例:
obj = cast(id(d), POINTER(PyDictObject)).contents
PyDictKeysObject的一个实例是:
key_obj = obj.ma_keys.contents
存储在字典槽0中的键的指针是:
key_obj.dk_entries[0].me_key
使用这些类的程序,以及探测每个插入字典的键的哈希冲突的例程,可以在这里找到。我的代码是对Brandon Rhodes为Python 2.x编写的代码的修改。他的代码在这里。