Python Numpy：保存的数组加载方式不同

Question

我正在尝试保存一个数组，使用的是

print myArray.shape, myArray.dtype # returns (yyy, xxx) uint8
numpy.save('savedFile.npy',myArray)

然后再用

myArray = numpy.load('savedFile.npy')
print myArray.shape, myArray.dtype # returns (yyy, ) object

把它加载回来。我该如何让这个数组的形状和数据类型和之前一样呢？

谢谢！

--- 编辑 ---

这里是我遇到的问题：

import numpy as np
import cv2, os.path

allImageIDs = []
allImages = []
countImagesMax = 20
countImages = 0
while countImages < countImagesMax:
  image = np.uint8(np.random.randint(2, size=(144,192)) *255)
  allImages.append(np.reshape(image, (image.shape[0]*image.shape[1])))
  allImageIDs.append(countImages)
  countImages += 1

myArray = [np.array(allImages), np.array(allImageIDs)]

if not os.path.exists("savedFile.npy"):
  np.save('savedFile.npy',myArray)
  print  myArray[0].shape, myArray[0].dtype # returns (yyy, xxx) uint8
else:
  myArray = np.load('savedFile.npy')
  print  myArray[0].shape, myArray[0].dtype # returns (yyy, ) object

Answer 1

评论区的讨论让我找到了答案，决定使用 np.savez 而不是 np.save。感谢大家的评论。

import numpy as np
import cv2, os.path

allImageIDs = []
allImages = []
countImagesMax = 20
countImages = 0
while countImages < countImagesMax:
  image = np.uint8(np.random.randint(2, size=(144,192)) *255)
  allImages.append(np.reshape(image, (image.shape[0]*image.shape[1])))
  allImageIDs.append(countImages)
  countImages += 1

myArray = [np.array(allImages), np.array(allImageIDs)]

if not os.path.exists("savedFile.npz"):
  np.savez('savedFile.npz', images=myArray[0], ids=myArray[1])
  print  myArray[0].shape, myArray[0].dtype # returns (yyy, xxx) uint8
else:
  npzfile = np.load('savedFile.npz')
  myArray = [npzfile['images'], npzfile['ids']]
  print  myArray[0].shape, myArray[0].dtype # returns (yyy, xxx) uint8