Django urls 返回404错误

Question

Django在我访问网站上的“blog/”时总是给我一个404错误，但我已经定义了我想要的URL，它们应该是匹配的。

主urls.py文件：

from django.conf.urls import patterns, include, url

from django.contrib import admin
admin.autodiscover()
from blog import views

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'mySiteProject.views.home', name='home'),
    # url(r'^blog/', include('blog.urls')),

    url(r'^blog/', include('blog.urls')),
    url(r'^admin/', include(admin.site.urls)),
)

blog.urls.py文件：

from django.conf.urls import patterns,url
from blog import views

urlpatterns = patterns(
    url(r'^$',views.index,name='index')
)

404错误页面：

Page not found (404)
Request Method:     GET
Request URL:    http://localhost:8000/blog/

Using the URLconf defined in mySiteProject.urls, Django tried these URL patterns, in this order:

    ^admin/

The current URL, blog/, didn't match any of these.

网站结构：

mySiteProject
    blog
        admin.py
        models.py
        tests.py
        views.py
        urls.py
        __init__.py
    mySiteProject
        wsgi.py
        settings.py
        urls.py
        __init__.py
    manage.py
    db.sqlite3

已安装的应用：

INSTALLED_APPS = (
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',

    'blog'
)

Answer 1

patterns 这个东西需要一个前缀作为第一个参数，后面可以跟零个或多个参数。所以这段代码：

urlpatterns = patterns(url(r'^$',views.index,name='index'))  # won't work

在 blog.urls.py 文件里应该看起来像这样：

urlpatterns = patterns('', url(r'^$', views.index, name='index'))  # now has a prefix as first argument

现在的状态下，blog.urls.py 里的 patterns 函数会返回一个空的 pattern_list，这就意味着 url(r'^blog/', include('blog.urls')) 不会返回任何模式。