在散点图中绘制感兴趣区域并打印matplotlib中包含的点
在一个散点图矩阵中,我想画一个感兴趣的区域(ROI),并打印出这个区域内的点。目前,我可以在子图中画出区域,但我不知道怎么获取并打印出那些在这个区域里的点。画区域时,需要按住 shift
键和左键鼠标。要关闭这个区域,则需要在按住 shift
键的同时,点击右键。关于如何打印出ROI内的点(类似于 LassoSelector演示 的功能),任何建议都非常感谢!提前谢谢大家!!
以下是代码:
from pylab import *
class ROI:
def __init__(self, axes, fig):
self.previous_point = []
self.start_point = []
self.end_point = []
self.line = None
self.fig = fig
self.fig.canvas.draw()
def motion_notify_callback(self, event):
if event.inaxes:
axes = event.inaxes
x, y = event.xdata, event.ydata
if event.button == None and self.line != None and event.key == 'shift': # #Move line around
self.line.set_data([self.previous_point[0], x],
[self.previous_point[1], y])
self.fig.canvas.draw()
elif event.button == 1 and event.key == 'shift': # Free Hand Drawing
line = Line2D([self.previous_point[0], x],
[self.previous_point[1], y])
axes.add_line(line)
self.previous_point = [x, y]
self.fig.canvas.draw()
def button_press_callback(self, event):
if event.inaxes:
x, y = event.xdata, event.ydata
axes = event.inaxes
if (event.key == 'shift') and (event.button == 1): # If you press the right button
if self.line == None: # if there is no line, create a line
self.line = Line2D([x, x],
[y, y],
marker = 's')
self.start_point = [x,y]
self.previous_point = self.start_point
axes.add_line(self.line)
self.fig.canvas.draw()
# add a segment
else: # if there is a line, create a segment
self.line = Line2D([self.previous_point[0], x],
[self.previous_point[1], y],
marker = 'o')
self.previous_point = [x,y]
event.inaxes.add_line(self.line)
self.fig.canvas.draw()
if (event.button == 3) and (event.key == 'shift') and (self.line != None): # close the loop
self.line.set_data([self.previous_point[0], self.start_point[0]],
[self.previous_point[1], self.start_point[1]])
axes.add_line(self.line)
self.fig.canvas.draw()
self.line = None
def main():
data = np.random.rand(100,4)
plt.close("all")
x, y = data[:, 0], data[:, 1]
x1, y1 = data[:,2], data[:, 3]
fig, axes = plt.subplots(ncols=2, nrows=1)
for ax, marker in zip(axes.flat, ['o', 'o']):
axes.flat[0].plot(x, y, 'r', ls='', marker=marker, picker=3)
axes.flat[1].plot(x, x1,'r', ls='', marker=marker, picker=3)
cursor = ROI(ax, fig)
#axes.set_title(" shift+left click: line segment shift+left pressed: doodle shift+right click: close region")
fig.canvas.mpl_connect('motion_notify_event', cursor.motion_notify_callback)
fig.canvas.mpl_connect('button_press_event', cursor.button_press_callback)
show()
if __name__ == "__main__":
main()
1 个回答
1
我觉得matplotlib有一个很不错的功能,叫做matplotlib.nxutils,可以用来检查某些点是否在多边形内部。
http://matplotlib.org/faq/howto_faq.html#test-whether-a-point-is-inside-a-polygon
你可以把你的感兴趣区域(ROI)转换成一个多边形,然后使用nx.points_inside_poly来检查。
(编辑)不过matplotlib.nxutils已经被淘汰,换成了matplotlib.path.Path.contains_points。我之前不知道这个,谢谢提醒。这里有一小段代码示例,使用了Path.contains_points。
from pylab import *
from matplotlib.path import Path
import matplotlib.patches as patches
data = np.random.rand(100,4)
verts = [(0.3, 0.7), (0.3, 0.3), (0.7, 0.3), (0.7, 0.7)]
path1 = Path(verts)
index = path1.contains_points(data[:,:2])
print data[index, :2]
plot(data[:,0],data[:,1], 'b.')
patch = patches.PathPatch(path1, facecolor='orange', lw=2)
gca().add_patch(patch)
plot(data[index,0], data[index,1], 'r.')
show()