基于Mixin列的SQLalchemy联合继承查询
我有一个声明式的类结构,长得像这样:
class BaseClass(Base):
Column A
Column B
class Mixin(object):
Column C
class ItemA(BaseClass):
Column D
class ItemB(Mixin, BaseClass):
pass
class ItemC(Mixin, BaseClass):
Column E
有没有办法让我使用 with_polymorphic
,这样我就可以根据 Column C
在所有的 Items
中进行查询,而不需要明确知道我有哪些 Item
?就像是这样
mixin_poly = with_polymorphic(base = BaseClass, classes = MixinClass.__subclasses__())
假设在导入时,所有 MixinClass
的派生类都已经被导入,然后再声明 with_polymorphic
。
编辑 注意,我省略了关于联合表继承的基础代码,但假设它已经正确设置,这样做
poly_base = with_polymorphic(base = BaseClass, classes = '*')
session.query(poly_base).filter(BaseClass.a == value, ...)
就能按预期从 BaseClass
查询列。关键是能够以相同的方式查询继承了 Mixin
类的子类中的公共列。
1 个回答
5
from sqlalchemy import *
from sqlalchemy.orm import *
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import inspect
Base = declarative_base()
class BaseClass(Base):
__tablename__ = 'base'
id = Column(Integer, primary_key=True)
type = Column(String)
a = Column(Integer)
b = Column(Integer)
__mapper_args__ = {"polymorphic_on": type}
class Mixin(object):
c = Column(Integer)
class ItemA(BaseClass):
__tablename__ = 'a'
id = Column(ForeignKey('base.id'), primary_key=True)
d = Column(Integer)
__mapper_args__ = {"polymorphic_identity": 'a'}
class ItemB(Mixin, BaseClass):
__tablename__ = 'b'
id = Column(ForeignKey('base.id'), primary_key=True)
__mapper_args__ = {"polymorphic_identity": 'b'}
class ItemC(Mixin, BaseClass):
__tablename__ = 'c'
id = Column(ForeignKey('base.id'), primary_key=True)
e = Column(Integer)
__mapper_args__ = {"polymorphic_identity": 'c'}
e = create_engine("sqlite://", echo=True)
Base.metadata.create_all(e)
def magic_w_poly(base):
insp = inspect(base)
w_poly = []
crit = []
for mapper in insp.self_and_descendants:
if "c" in mapper.c:
w_poly.append(mapper)
crit.append(mapper.c.c)
w_col_c = with_polymorphic(base, w_poly)
def comparator(value):
return or_(
crit_elem == value
for crit_elem in crit
)
return w_col_c, comparator
s = Session(e)
w_col, comp = magic_w_poly(BaseClass)
print s.query(w_col).filter(comp(35))
最后的查询:
SELECT base.id AS base_id, base.type AS base_type, base.a AS base_a, base.b AS base_b, b.id AS b_id, b.c AS b_c, c.id AS c_id, c.c AS c_c, c.e AS c_e
FROM base LEFT OUTER JOIN b ON base.id = b.id LEFT OUTER JOIN c ON base.id = c.id
WHERE b.c = :c_1 OR c.c = :c_2