在raw_input()中显示输出

1 投票
1 回答
1224 浏览
提问于 2025-04-17 21:14

我正在实现一个聊天服务器,目前我有一份客户端套接字的列表,想通过这些套接字发送信息。问题是,客户端在输入状态(raw_input())下,只有在客户端自己输入内容后,才能将消息通过服务器转发,而此时每个客户端的接收缓冲区会一直被填满,直到它自己输入内容为止,这时它才会把接收到的内容作为一整行打印出来。

我希望每个客户端能够立即看到自己缓冲区里的内容,即使它们还在输入状态中。

以下是我的输出:

cli1.py

Your Message: test
Your Message: Received  "'test'"
test
Received  "'test'"
Your Message: 

cli2.py

Your Message: test
Your Message: Received  "'test'"
1
Received  "'test''test'"
Your Message: 

server.py

Server is running......
('127.0.0.1', 58919) is Connected
('127.0.0.1', 58920) is Connected
Received Message 'test'
we have connected:  <socket._socketobject object at 0x1004b6f30>
we have connected:  <socket._socketobject object at 0x1004e98a0>
Received Message 'test'
we have connected:  <socket._socketobject object at 0x1004b6f30>
we have connected:  <socket._socketobject object at 0x1004e98a0>
Received Message 'test'
we have connected:  <socket._socketobject object at 0x1004b6f30>
we have connected:  <socket._socketobject object at 0x1004e98a0>
Received Message '1'
we have connected:  <socket._socketobject object at 0x1004b6f30>
we have connected:  <socket._socketobject object at 0x1004e98a0>

还有我的实际代码:

cli1 = cli2:

from socket import *
from threading import Thread
import sys

def iamclient():
    message = raw_input("Your Message: ")
    s.send(message)
    reply = s.recv(1024) # 1024 is max data that can be received
    print "Received ", repr(reply)

HOST = ''
PORT = 8003

s = socket(AF_INET, SOCK_STREAM)
try:
    s.connect((HOST, PORT)) # client-side, connects to a host
except:
    print 'Max capacity reached, try again later'
    s.close()
    sys.exit()


Thread(target=iamclient).start()
while True:
    iamclient()

s.close()

server.py

from socket import *
from threading import Thread

def clientHandler():
    conn, addr = s.accept()
    connlist.append(conn)
    print addr, "is Connected"
    while 1:
        data = conn.recv(1024)
        if not data:
            break
        print "Received Message", repr(data)
        for i in connlist:
            print "we have connected: ",i
            i.send(repr(data))


HOST = '' #localhost
PORT = 8003

s = socket(AF_INET, SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(2)

connlist = []

print "Server is running......"

#Thread(target=clientHandler).start()
#Thread(target=clientHandler).start()
#Thread(target=clientHandler).start()

for i in range(2):
    Thread(target=clientHandler).start()

s.close()

1 个回答

0

因为(正如@thefourtheye所说)raw_input会在主线程上阻塞输入,所以你需要创建一个单独的线程来打印消息。

多线程解决方案:

>>> def print_message():
    time.sleep(5)
    print "message"


>>> bgThread = Thread(target=print_message)
>>> bgThread.start()
>>> x = raw_input()
message
input is entered here
>>> print x
input is entered here

使用一个单独的Thread来接收和打印消息。

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