python mock: @wraps(f) 问题
我想测试我写的一个简单的装饰器:
它的样子是这样的:
#utilities.py
import other_module
def decor(f):
@wraps(f)
def wrapper(*args, **kwds):
other_module.startdoingsomething()
try:
return f(*args, **kwds)
finally:
other_module.enddoingsomething()
return wrapper
然后我用python-mock来测试它:
#test_utilities.py
def test_decor(self):
mock_func = Mock()
decorated_func = self.utilities.decor(mock_func)
decorated_func(1,2,3)
self.assertTrue(self.other_module.startdoingsomething.called)
self.assertTrue(self.other_module.enddoingsomething.called)
mock_func.assert_called_with(1,2,3)
但是它给我返回了:
Traceback (most recent call last):
File "test_utilities.py", line 25, in test_decor
decorated_func = Mock(wraps=self.utilities.decor(mock_func))
File "utilities.py", line 35, in decor
@wraps(f)
File "/usr/lib/python2.7/functools.py", line 33, in update_wrapper
setattr(wrapper, attr, getattr(wrapped, attr))
File "/usr/local/lib/python2.7/dist-packages/mock.py", line 660, in __getattr__
raise AttributeError(name)
AttributeError: __name__
我知道functools.wraps()
只是一个辅助工具。所以如果我把它去掉,测试就能正常工作了。
我能让Mock和functools.wraps()一起正常工作吗?
Python 2.7.3
1 个回答
16
只需要给你的模拟对象加上那个属性就行:
mock_func.__name__ = 'foo'
就这么简单。
演示:
>>> from functools import wraps
>>> from mock import Mock
>>> def decor(f):
... @wraps(f)
... def wrapper(*args, **kwds):
... return f(*args, **kwds)
... return wrapper
...
>>> mock_func = Mock()
>>> decor(mock_func)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 2, in decor
File ".../opt/lib/python2.7/functools.py", line 33, in update_wrapper
setattr(wrapper, attr, getattr(wrapped, attr))
File ".../lib/python2.7/site-packages/mock.py", line 660, in __getattr__
raise AttributeError(name)
AttributeError: __name__
>>> mock_func.__name__ = 'foo'
>>> decor(mock_func)
<function foo at 0x10c4321b8>
设置 __name__
是完全可以的;@wraps
装饰器会把 __name__
属性复制到包装函数上,而在函数对象中,这个属性通常是一个字符串。无论如何,这个属性在函数上是可以写的,只要你使用字符串,function.__name__
可以设置成任何值。