Django request.user 无法解析 SimpleLazyObject

Question

我在我的Django应用中有一个方法，它通过用户ID来查找一个对象。这个方法是通过AJAX调用的。当我登录到一个有效的用户账户时，无论我怎么尝试，request.user的结果都是一个django.utils.functional.SimpleLazyObject对象，这导致我无法获取我想要的数据（出现了SkillEntry匹配的查询不存在的错误，尽管它实际上是存在的）。我尝试了Django：按用户过滤草稿导致错误中的解决方案，但没有成功。

我该如何让用户指向一个实际的用户对象实例呢？

视图代码：

@login_required
def skill_set(request, name):
    skill = Skill.objects.get(slug=name) # Found.
    level = 0
    user = request.user
    if request.method == 'POST':
        if user.is_authenticated():
            entry = SkillEntry.objects.get(user=user.pk, skill=skill) # Not found.
            entry.level = request.POST['level']
            entry.save()
            return HttpResponse(status=200)
    else:
        return HttpResponseForbidden()

JavaScript客户端代码：

function setSkill(skill, value) {
  var req = new XMLHttpRequest();
  req.open("POST", "/skill/" + skill + "/set/", true);
  csrftoken = getCookie('csrftoken');
  req.setRequestHeader("X-CSRFToken", csrftoken);
  req.send('level=' + value);
  var elem = document.getElementById('level');
  elem.innerHTML = "My skill level is " + value + ".";
}

我是不是需要在请求中设置什么东西来保持会话信息？我可以发誓我在Django的早期版本中成功做过类似的事情。我现在使用的是1.4.3版本。

编辑：

以下是我在models.py中的模型定义：

class Skill(models.Model):
    name = models.CharField(max_length=100)
    slug = models.CharField(max_length=100, blank=True)
    keywords = models.CharField(max_length=120, blank=True, help_text='List of additional keywords this skill should show up for in search')
    description = models.TextField(null=True, blank=True)
    parent = models.ForeignKey('Skill', null=True, blank=True, help_text='Parent skill.  Leave blank if this is a root category.')

    def save(self, *args, **kwargs):
        if not self.id:
            self.slug = slugify(self.name)
        super(Skill, self).save(*args, **kwargs)

    def __unicode__(self):
        return self.name

    class Meta:
        ordering = ('name',)

class SkillEntry(models.Model):
    skill = models.ForeignKey('Skill')
    level = models.IntegerField()
    user = models.ForeignKey(User)
    last_updated = models.DateField(auto_now=True)

    class Meta:
        verbose_name_plural = 'Skill Entries'
        ordering = ('skill__name',)

    def __unicode__(self):
        return self.user.username + ' knows ' + self.skill.name + ' at level ' + str(self.level)

django error handling ajax session management user authentication model definition simplelazyobject skillentry

Django request.user 无法解析 SimpleLazyObject

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