如何打印仅含一个元音的单词？

Question

这是我目前写的代码，但因为我完全搞不清楚，所以它根本没有做到我想要的效果：

vowels = 'a','e','i','o','u','y'
#Consider 'y' as a vowel

input = input("Enter a sentence: ")

words = input.split()
if vowels == words[0]:
    print(words)

比如说，输入是这样的：

"this is a really weird test"

我只想让它打印出：

this, is, a, test

因为它们只包含一个元音字母。

Answer 1

你可以把所有的元音字母都换成一个元音字母，然后数一数这个元音字母的数量：

import string
trans = string.maketrans('aeiouy','aaaaaa')
strs = 'this is a really weird test'
print [word for word in strs.split() if word.translate(trans).count('a') == 1]

Answer 2

试试这个：

vowels = set(('a','e','i','o','u','y'))

def count_vowels(word):
    return sum(letter in vowels for letter in word)

my_string = "this is a really weird test"

def get_words(my_string):
    for word in my_string.split():
        if count_vowels(word) == 1:
            print word

结果：

>>> get_words(my_string)
this
is
a
test

Answer 3

这里还有一个选择：

import re

words = 'This sentence contains a bunch of cool words'

for word in words.split():
    if len(re.findall('[aeiouy]', word)) == 1:
        print word

输出结果：

This
a
bunch
of
words