C#中的Python控制台

Question

我正在尝试创建一个控件，用来实现一个Python控制台。不过，遗憾的是，它没有接收到任何Python的输出。

    Queue<string> qstring = new Queue<string>();
    Thread thread;
    Process prc;
    void pythonmain()
    {
        if (DesignMode) return;
        prc = new Process();
        prc.StartInfo.FileName = "python";
        prc.StartInfo.Arguments = " -u";
        prc.StartInfo.RedirectStandardInput = true;
        prc.StartInfo.RedirectStandardOutput = true;
        prc.StartInfo.RedirectStandardError = true;
        prc.StartInfo.UseShellExecute = false;
        prc.StartInfo.CreateNoWindow = true;

        prc.EnableRaisingEvents = true;
        prc.OutputDataReceived += new DataReceivedEventHandler(prc_OutputDataReceived);
        prc.ErrorDataReceived += new DataReceivedEventHandler(prc_ErrorDataReceived);
        prc.SynchronizingObject = this;

        prc.Start();
        prc.BeginOutputReadLine();
        prc.BeginErrorReadLine();




        while (!prc.HasExited)
        {
            lock (qstring)
            {
                if (qstring.Count > 0) prc.StandardInput.Write(qstring.Dequeue()+"\n");
            }
        }


        prc.WaitForExit();
    }

    void prc_ErrorDataReceived(object sender, DataReceivedEventArgs e)
    {
        if (e.Data != null)
        {
            richTextBox1.BeginInvoke(new Action<string>((s) => richTextBox1.AppendText(s)),e.Data);
        }
    }

    void prc_OutputDataReceived(object sender, DataReceivedEventArgs e)
    {
        System.Diagnostics.Process p = (Process)sender;

        if (e.Data != null)
        {
            richTextBox1.BeginInvoke(new Action<string>((s) => richTextBox1.AppendText(s)), e.Data);
        }
    }


    public PyConsoleControl()
    {
        InitializeComponent();
        if (!DesignMode)
        {
        thread = new Thread(pythonmain);
        thread.IsBackground = true;
        thread.Start();
        }
    }

    private void textBox1_KeyDown(object sender, KeyEventArgs e)
    {
        if (e.KeyCode == Keys.Enter)
        {
            lock (qstring)
            {
                qstring.Enqueue(textBox1.Text);
            }
            textBox1.Clear();
        }
    }
}

正如你所看到的，我正在创建一个新的线程来启动一个Python解释器，但没有返回任何Python的输出。我该怎么解决这个问题呢？

Answer 1

要小心哦，你得确认这个进程确实已经启动。为此，你应该检查一下启动方法的结果。如果返回的是true，说明进程已经启动；如果是false，那就表示没有启动。

Answer 2

一定要看看 IronPython，它几乎肯定能满足你的需求。

举个例子：

using System;
using IronPython.Hosting;
using Microsoft.Scripting.Hosting;
// we get access to Action and Func on .Net 2.0
using Microsoft.Scripting.Utils;

namespace TestCallIronPython
{
    class Program
    {
        public static void Main(string[] args)
        {
            Console.WriteLine("Hello World!");
            ScriptEngine pyEngine = Python.CreateEngine();
            ScriptScope pyScope = pyEngine.CreateScope();
            pyScope.SetVariable("test", "test me");

            string code = @"
             print 'test = ' + test
             class MyClass:
             def __init__(self):
               pass

             def somemethod(self):
               print 'in some method'

             def isodd(self, n):
               return 1 == n % 2
           ";
           ScriptSource source = pyEngine.CreateScriptSourceFromString(code);
           CompiledCode compiled = source.Compile();
           compiled.Execute(pyScope);

           // Get the Python Class
           object MyClass = pyEngine.Operations.Invoke(pyScope.GetVariable("MyClass"));
           // Invoke a method of the class
           pyEngine.Operations.InvokeMember(MyClass, "somemethod", new object[0]);

           // create a callable function to 'somemethod'
           Action SomeMethod2 = pyEngine.Operations.GetMember<Action>(MyClass, "somemethod");
           SomeMethod2();

           // create a callable function to 'isodd'
           Func<int, bool> IsOdd = pyEngine.Operations.GetMember<Func<int, bool>>(MyClass, "isodd");
           Console.WriteLine(IsOdd(1).ToString());
           Console.WriteLine(IsOdd(2).ToString());

           Console.Write("Press any key to continue . . . ");
           Console.ReadKey(true);
       }
   }
}

这个例子直接来自于 这里。