如何根据掷骰子的得分对姓名进行排序

Question

我正在做一个程序，这个程序会生成三个不同的整数，并把它们分别分配给不同的值，以决定谁先、谁第二、谁最后。在这个例子中，我假设有三个不同的玩家，每个人都掷一个“十面骰子”。掷出点数最高的玩家先行动，第二高的玩家第二行动，第三高的玩家最后行动。现在一切看起来都还不错，但我已经得到了这些值，却不知道怎么把它们排列好，以便开始让玩家轮流进行游戏。我很感激任何建议。

这是我目前写的代码：

import sys
import os
import random
import time

os.system('clear')
print ('Welcome!  Please type Player 1\'s name!: ')
playerOne = input()
print ('Okay!  Please type Player 2\'s name!: ')
playerTwo = input()
print ('Fantastic!  Finally, please type Player 3\'s name!: ')
playerThree = input()
os.system('clear')
print()
time.sleep(2)

def startFightRoll():
    playerOneRoll = random.randint(1,10)
    time.sleep(.5)
    print('Okay, let\'s roll a ten-sided die to see who gets to go first!')
    print()
    time.sleep(2)
    print ('<Ten-sided dice roll> ')
    print ('---------------------------------')
    print (playerOne + ' rolls ' + str(playerOneRoll))
    print()
    print()
    playerTwoRoll = random.randint(1,10)
    time.sleep(2)
    print ('<Ten-sided dice roll> ')
    print ('---------------------------------')
    print (playerTwo + ' rolls ' + str(playerTwoRoll))
    print()
    print()
    playerThreeRoll = random.randint(1,10)
    time.sleep(2)
    print ('<Ten-sided dice roll> ')
    print ('---------------------------------')
    print (playerThree + ' rolls ' + str(playerThreeRoll))

startFightRoll()

关于下面的讨论；

好吧，我是新手，所以请原谅我的代码——它不是很高效，我还在适应中。我添加了一些部分来处理1）玩家在名字字段中什么都不输入，和2）掷骰子时出现平局的情况。我还创建了一个按降序排列的骰子点数列表，但现在我需要找到一种方法，把这些点数和产生它们的用户关联起来。任何关于如何正确做到这一点的建议都非常感谢；

import sys
import os
import random
import time

os.system('clear')


def playerOneName():
    global playerOne
    playerOne = input()
    if len(playerOne) < 1:
        print('Please enter your name, Player 1!')
        playerOneName()

def playerTwoName():
    global playerTwo
    playerTwo = input()
    if len(playerTwo) < 1:
        print('Please enter your name, Player 2!')
        playerTwoName()

def playerThreeName():
    global playerThree
    playerThree = input()
    if len(playerThree) < 1:
        print('Please enter your name, Player 3!')
        playerThreeName()

os.system('clear')
print()
time.sleep(2)
def startFightRoll():
    global playerOneRoll
    global playerTwoRoll
    global playerThreeRoll
    playerOneRoll = random.randint(1,10)
    time.sleep(.5)
    print('Okay, let\'s roll a ten-sided die to see who gets to go first!')
    print()
    time.sleep(2)
    print ('<Ten-sided dice roll> ')
    print ('---------------------------------')
    print (playerOne + ' rolls ' + str(playerOneRoll))
    print()
    print()
    playerTwoRoll = random.randint(1,10)
    time.sleep(2)
    print ('<Ten-sided dice roll> ')
    print ('---------------------------------')
    print (playerTwo + ' rolls ' + str(playerTwoRoll))
    print()
    print()
    playerThreeRoll = random.randint(1,10)
    time.sleep(2)
    print ('<Ten-sided dice roll> ')
    print ('---------------------------------')
    print (playerThree + ' rolls ' + str(playerThreeRoll))
    if playerOneRoll == playerTwoRoll:
        print ('There\'s a tie, rolling again!')
        time.sleep(3)
        os.system('clear')
        startFightRoll()
    if playerOneRoll == playerThreeRoll:
        print ('There\'s a tie, rolling again!')
        time.sleep(3)
        os.system('clear')
        startFightRoll()
    if playerTwoRoll == playerThreeRoll:
        print ('There\'s a tie, rolling again!')
        os.system('clear')
        time.sleep(3)
        startFightRoll()    

    O = [playerOneRoll, playerTwoRoll, playerThreeRoll]
    O = sorted(O, reverse = True)
    print (O)

print ('Welcome!  Please type Player 1\'s name!: ')
playerOneName()
print ('Okay!  Please type Player 2\'s name!: ')
playerTwoName()
print ('Fantastic!  Finally, please type Player 3\'s name!: ')
playerThreeName()
os.system('clear')
startFightRoll()

用户输入编程新手游戏逻辑平局处理降序排列掷骰子整数生成玩家排序

如何根据掷骰子的得分对姓名进行排序

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