用于播放固定频率声音的Python库
我家里有蚊子问题。这通常和程序员没什么关系;不过,我看到一些设备声称可以通过播放17Khz的音调来驱赶这些讨厌的生物。我想用我的笔记本电脑来实现这个。
一种方法是制作一个包含单一固定频率音调的MP3文件(这可以通过Audacity轻松完成),然后用Python库打开它并重复播放。
第二种方法是使用电脑内置的扬声器播放声音。我想找类似于QBasic中的Sound功能:
SOUND 17000, 100
有没有这样的Python库呢?
6 个回答
5
我把我的代码放在这里,因为这样可以帮助程序员更清楚地理解代码是怎么工作的。代码本身就有解释:
#!/usr/bin/env python3
import pyaudio
import struct
import math
FORMAT = pyaudio.paInt16
CHANNELS = 2
RATE = 44100
p = pyaudio.PyAudio()
def data_for_freq(frequency: float, time: float = None):
"""get frames for a fixed frequency for a specified time or
number of frames, if frame_count is specified, the specified
time is ignored"""
frame_count = int(RATE * time)
remainder_frames = frame_count % RATE
wavedata = []
for i in range(frame_count):
a = RATE / frequency # number of frames per wave
b = i / a
# explanation for b
# considering one wave, what part of the wave should this be
# if we graph the sine wave in a
# displacement vs i graph for the particle
# where 0 is the beginning of the sine wave and
# 1 the end of the sine wave
# which part is "i" is denoted by b
# for clarity you might use
# though this is redundant since math.sin is a looping function
# b = b - int(b)
c = b * (2 * math.pi)
# explanation for c
# now we map b to between 0 and 2*math.PI
# since 0 - 2*PI, 2*PI - 4*PI, ...
# are the repeating domains of the sin wave (so the decimal values will
# also be mapped accordingly,
# and the integral values will be multiplied
# by 2*PI and since sin(n*2*PI) is zero where n is an integer)
d = math.sin(c) * 32767
e = int(d)
wavedata.append(e)
for i in range(remainder_frames):
wavedata.append(0)
number_of_bytes = str(len(wavedata))
wavedata = struct.pack(number_of_bytes + 'h', *wavedata)
return wavedata
def play(frequency: float, time: float):
"""
play a frequency for a fixed time!
"""
frames = data_for_freq(frequency, time)
stream = p.open(format=FORMAT, channels=CHANNELS, rate=RATE, output=True)
stream.write(frames)
stream.stop_stream()
stream.close()
if __name__ == "__main__":
play(400, 1)
29
PyAudiere 是一个简单的跨平台解决方案,用来解决以下问题:
>>> import audiere
>>> d = audiere.open_device()
>>> t = d.create_tone(17000) # 17 KHz
>>> t.play() # non-blocking call
>>> import time
>>> time.sleep(5)
>>> t.stop()
pyaudiere.org 网站已经关闭了。你可以通过这个链接找到网站的存档,以及适用于 Python 2 的安装包(适用于 Debian 和 Windows)。比如,你可以在这里下载源代码 pyaudiere-0.2.tar.gz
。
如果你想在 Linux、Windows 和 OSX 上同时支持 Python 2 和 3,可以使用pyaudio
模块来代替:
#!/usr/bin/env python
"""Play a fixed frequency sound."""
from __future__ import division
import math
from pyaudio import PyAudio # sudo apt-get install python{,3}-pyaudio
try:
from itertools import izip
except ImportError: # Python 3
izip = zip
xrange = range
def sine_tone(frequency, duration, volume=1, sample_rate=22050):
n_samples = int(sample_rate * duration)
restframes = n_samples % sample_rate
p = PyAudio()
stream = p.open(format=p.get_format_from_width(1), # 8bit
channels=1, # mono
rate=sample_rate,
output=True)
s = lambda t: volume * math.sin(2 * math.pi * frequency * t / sample_rate)
samples = (int(s(t) * 0x7f + 0x80) for t in xrange(n_samples))
for buf in izip(*[samples]*sample_rate): # write several samples at a time
stream.write(bytes(bytearray(buf)))
# fill remainder of frameset with silence
stream.write(b'\x80' * restframes)
stream.stop_stream()
stream.close()
p.terminate()
示例:
sine_tone(
# see http://www.phy.mtu.edu/~suits/notefreqs.html
frequency=440.00, # Hz, waves per second A4
duration=3.21, # seconds to play sound
volume=.01, # 0..1 how loud it is
# see http://en.wikipedia.org/wiki/Bit_rate#Audio
sample_rate=22050 # number of samples per second
)
这是一个修改过的版本(支持 Python 3),来源于这个 AskUbuntu 的回答。