Python:未绑定的方法receive()必须以MessageNet实例作为第一个参数(而不是MessageGlobal实例)

0 投票
2 回答
1411 浏览
提问于 2025-04-17 14:56

我遇到了一个问题,这是我的 Django 视图。

 def home(request):
        try:
            from_number  = request.GET['from_number']
            to_number  = request.GET['to_number']
            messagetext  = request.GET['msg_text']
            date_time  = request.GET['date_time']
            date_received  = request.GET['date_received']
            status = 0
        except:
            LOG_ERROR('Invalid Parameter')

            #Return to some product page or 500 error with message
            #pass    #  return some value  after discussing with sir 
     #      #Based on from number identify the Vmn and his class anc class the respective receieve method of that class
        if from_number !=None  and to_number != None:
            try:getvmn = ServiceProvider.objects.get(status = False)
            except:
                LOG_FATAL("VMN doesn't exists ")
                getvmn = False
            if getvmn:
                print "-=-=-=-=-==-=-=-==================="
    #           get_related_class = ServiceProvider.objects.filter(id  = getvmn.merchant,status = False)
                get_related_class = ServiceProvider.objects.get(status = False)
                b = SMSMgr()
                for objec in b._allsp:
                    if objec.class_Name == 'MessageNet':
                       # messageglobalobject  =     
                        MessageNet.receive(MessageGlobal(from_number,to_number,messagetext,date_received,status))

这是 smsmessage.py 文件。

class MessageGlobal():
    def __init__(self,from_number,to_number,messagetext,date,status = None):
        self.messagetext = messagetext
        self.to_number = to_number
        self.from_number = from_number
        self.date = date
        self.status = status

这是 MessageNet 类。

class MessageNet():
    def __init__(self,username,password,sendingurl,class_Name):
        self.username = username
        self.password = password
        self.messagetext = None
        self.sendingurl = sendingurl
        self.class_Name = class_Name
        self.PhoneNumber = None
       # self.apiurl = apiurl

    def send(self,mg):

        payload = {'username': self.username, 'Pwd': self.password,'PhoneNumber':mg.tonumber,'PhoneMessage':mg.messagetext}
        r = requests.get(self.sendingurl, params=payload)
        LOG_INFO("Message sent to %s  via  %s", self.PhoneNumber,'Messagenet')
        #   Call to ms manager 

    def receive(self,getmessageobject):

        print "receive and notify the user "    

我在这一行出现了错误。

MessageNet.receive(MessageGlobal(from_number,to_number,messagetext,date_received,status))
of my views .

我想把一个 MessageGlobal 对象传递给 receive 方法,这样我就可以在 MessageNet 类的 receive 方法里面访问它们。

请告诉我,为什么我会遇到这个错误。

2 个回答

0

你遇到这个问题是因为你把一个 MessageGlobal 的实例传给了 MessageNet 的一个方法。你可以选择传一个 MessageNet 的实例,或者把这个方法改成一个普通的函数。

2

你是在一个类上调用实例方法,而不是在一个具体的实例上。你需要先创建一个 MessageNet 对象,然后在这个对象上调用 receive 方法,而不是直接在类上调用。

另外,你也可以把它改成类方法,但那样的话你就不能访问任何实例的属性(比如密码等)。

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