Python遍历多个列表并返回随机选择

Question

import random
def iterate_thru_list():
   i = 0  
   L1 = [1,2,3,4,5,6,7,8,9]
   L2=['a','b','c','d','e','f','g','h','i']
   L3= ['A','B','C','D','E','F','G','H','I']
   random.shuffle(L1)
   random.shuffle(L2)
   random.shuffle(L3)


   print ("List:")
   while i <= 5:
      for x, y, z in [(x,y,z) for x in L1 for y in L2 for z in L3]:
         print(x,y,z)
   i = i + 1

我想从几个不同的列表中随机选择一个数字或字母，然后返回一个包含三个独特字母或数字的“集合”。需要注意的是，while循环不太好用——它会一直循环，直到返回所有组合，这我也搞不懂。我可以用random.choice(L1或L2或L3)来返回x、y和z吗？有没有更简单的方法从多个列表中随机选择？谢谢你的帮助。

Answer 1

像这样吗？

L1 = [1,2,3,4,5,6,7,8,9]
L2 = ['a','b','c','d','e','f','g','h','i']
L3 = ['A','B','C','D','E','F','G','H','I']

from random import choice

for i in range(5):
    print list(map(choice, (L1, L2, L3)))

[4, 'h', 'A']
[7, 'b', 'G']
[3, 'c', 'C']
[6, 'f', 'H']
[5, 'b', 'A']