Python argparse 类型错误

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1 回答
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提问于 2025-04-17 13:59

我在玩Python里的argparse这个库。最开始我写了下面这样的代码:

group_gen.add_argument('--switch', nargs=2, metavar=('PARAM1', 'PARAM2'))

然后我把PARAM2去掉了,所以现在的代码变成了:

group_gen.add_argument('--switch', nargs=2, metavar=('PARAM1', 'PARAM2'))

接着,每当argparse需要打印帮助信息的时候,我就会遇到下面这个错误和堆栈跟踪信息:

Traceback (most recent call last):
  File "./script.py", line 20, in <module>
    args = parser.parse_args()
  File "/usr/lib/python2.7/argparse.py", line 1688, in parse_args
    args, argv = self.parse_known_args(args, namespace)
  File "/usr/lib/python2.7/argparse.py", line 1727, in parse_known_args
    self.error(str(err))
  File "/usr/lib/python2.7/argparse.py", line 2346, in error
    self.print_usage(_sys.stderr)
  File "/usr/lib/python2.7/argparse.py", line 2308, in print_usage
    self._print_message(self.format_usage(), file)
  File "/usr/lib/python2.7/argparse.py", line 2264, in format_usage
    return formatter.format_help()
  File "/usr/lib/python2.7/argparse.py", line 279, in format_help
    help = self._root_section.format_help()
  File "/usr/lib/python2.7/argparse.py", line 209, in format_help
    func(*args)
  File "/usr/lib/python2.7/argparse.py", line 317, in _format_usage
    action_usage = format(optionals + positionals, groups)
  File "/usr/lib/python2.7/argparse.py", line 449, in _format_actions_usage
    args_string = self._format_args(action, default)
  File "/usr/lib/python2.7/argparse.py", line 587, in _format_args
    result = ' '.join(formats) % get_metavar(action.nargs)
TypeError: not enough arguments for format string

我为什么会出现这个错误呢?

我一直搞不清楚发生了什么,后来我突然想到,可能是因为命令格式字符串的问题。

1 个回答

0

我觉得你的问题写错了,不过你可以试试这个:

group_gen.add_argument('--switch', nargs=1, metavar=('PARAM1'))

这就是你想要做的事情吗?

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