Python 和子进程
这是我正在做的一个脚本。它应该在下面的循环中运行一个 .exe 文件。(顺便说一下,不确定是否能看到,但 for el in ('90','52.6223',...) 是在循环外面的,它和其他部分形成了一个嵌套循环。)我不太确定顺序是否正确或者其他方面的问题。另外,当 .exe 文件运行时,它会输出一些内容,我需要把某一行打印到屏幕上(这就是你看到的 AspecificLine= ... 的原因)。如果有任何有用的回答,那就太好了!
for el in ('90.','52.62263.','26.5651.','10.8123.'):
if el == '90.':
z = ('0.')
elif el == '52.62263.':
z = ('0.', '72.', '144.', '216.', '288.')
elif el == '26.5651':
z = ('324.', '36.', '108.', '180.', '252.')
else el == '10.8123':
z = ('288.', '0.', '72.', '144.', '216.')
for az in z:
comstring = os.path.join('Path where .exe file is')
comstring = os.path.normpath(comstring)
comstring = '"' + comstring + '"'
comstringfull = comstring + ' -el ' + str(el) + ' -n ' + str(z)
print 'The python program is running this command with the shell:'
print comstring + '\n'
process = Popen(comstring,shell=True,stderr=STDOUT,stdout=PIPE)
outputstring = myprocesscommunicate()
print 'The command shell returned the following back to python:'
print outputstring[0]
AspecificLine=linecache.getline(' ??filename?? ', # ??
sys.stderr.write('az', 'el', 'AREA' ) # ??
1 个回答
1
使用 shell=True
是不对的,因为这样会不必要地调用系统的命令行。
相反,你应该这样做:
for el in ('90.','52.62263.','26.5651.','10.8123.'):
if el == '90.':
z = ('0.')
elif el == '52.62263.':
z = ('0.', '72.', '144.', '216.', '288.')
elif el == '26.5651':
z = ('324.', '36.', '108.', '180.', '252.')
else el == '10.8123':
z = ('288.', '0.', '72.', '144.', '216.')
for az in z:
exepath = os.path.join('Path where .exe file is')
exepath = os.path.normpath(comstring)
cmd = [exepath, '-el', str(el), '-n', str(z)]
print 'The python program is running this command:'
print cmd
process = Popen(cmd, stderr=STDOUT, stdout=PIPE)
outputstring = process.communicate()[0]
print 'The command returned the following back to python:'
print outputstring
outputlist = outputstring.splitlines()
AspecificLine = outputlist[22] # get some specific line. 23?
print AspecificLine