PyQt与Maya,线程设置为False?

1 投票
1 回答
2317 浏览
提问于 2025-04-17 13:07

我已经研究这个问题三天了,但一直没有找到解决办法。我对这些东西还很陌生,可能有些地方我没注意到。

这个问题涉及到:Maya.cmds、PyMel 和使用 QThread 或普通线程的 MEL 代码

这段代码是为了在“mayapy”这个 Python 解释器上运行的,它是跟随 Maya 的。我写了一个简短的例子,可以在多个实例中重现同样的错误。

一个按钮可以正常工作,另一个却不行。但它们运行的是同样的代码。

from PyQt4 import Qt

class doStuff( Qt.QThread ):
    taskProgress = Qt.pyqtSignal(int)

    # --------------------------------------------------------- #
    # Here things start to crash...
    def run( self ):

        # This works
        persp = mel.general.PyNode('persp')
        print persp.translateX.get()

        # This dont work
        poiLights = mel.general.ls( exactType="pointLight" ) 
        for light in poiLights:
            print light

        # This dont work
        geo = mel.general.PyNode('pPyramidShape1')
        print mel.modeling.polyEvaluate( geo, face=True )

        # Emit progress
        self.taskProgress.emit( 1 )

        return
    # END
    # --------------------------------------------------------- #

class ui( Qt.QWidget ):
    def __init__(self, parent=None):
        super(ui, self).__init__(parent)

        # Init QThread
        self.thread = doStuff()

        # Create Widgets
        buttonNo = Qt.QPushButton("Start - Dont work")
        buttonYes = Qt.QPushButton("Start - Works")

        # Setup Layout
        layout = Qt.QVBoxLayout()
        layout.addWidget( buttonYes )
        layout.addWidget( buttonNo )
        self.setLayout( layout )
        self.show()

        # --------------------------------
        # PROBLEM AREA: Button signals

        # This one dont work, but starts the thread correctly.
        self.connect( buttonNo, Qt.SIGNAL("clicked()"), self.thread.start )

        # This one works, but dont start the thread correctly.
        self.connect( buttonYes, Qt.SIGNAL("clicked()"), self.thread.run ) 

        # --------------------------------

        self.thread.taskProgress.connect( self.updateProgress )

        return

    # Feedback progress status
    def updateProgress( self, value ):
        print 'Current progress is:', value

        return

if __name__ == '__main__':

    import sys
    app = Qt.QApplication(sys.path)
    program = ui()

    # init maya
    import pymel.core as mel
    filePath = '/Users/ecker/Dropbox/Scripts/RibExporter/mayaScene3ani.ma'
    mel.openFile( filePath, f=True, o=True )

    sys.exit(app.exec_())

这段代码创建了两个按钮,按下时会执行同一个函数。一个按钮执行 thread.startthread.run

thread.start 会让线程正常工作,能够将数据反馈给 Qt 界面(比如进度条),但大部分 Maya 代码会开始返回各种错误,比如:

Traceback (most recent call last):
  File "/Users/ecker/Dropbox/Scripts/RibExporter/error_recreation2.py", line 22, in run
    poiLights = mel.general.ls( exactType="pointLight" ) 
  File "/Applications/Autodesk/maya2012/Maya.app/Contents/Frameworks/Python.framework/Versions/Current/lib/python2.6/site-packages/pymel/core/general.py", line 969, in ls
    res = _util.listForNone(cmds.ls(*args, **kwargs))
  File "/Applications/Autodesk/maya2012/Maya.app/Contents/Frameworks/Python.framework/Versions/Current/lib/python2.6/site-packages/pymel/internal/pmcmds.py", line 134, in wrappedCmd
    res = new_cmd(*new_args, **new_kwargs)
TypeError: Flag 'long' must be passed a boolean argument

这是一个布尔值参数,不管我尝试用什么格式和方式传递参数,它总是会给出类似的错误。在同一行 res = new_cmd(*new_args, **new_kwargs) 需要一个布尔值。

我需要让 thread start,而不仅仅是运行。除非有其他方法来处理线程,不然有没有什么解决办法?

1 个回答

4

Maya在处理线程时表现得不是很好。这里的关键是要使用maya.utils.executeInMainThreadWithResult这个方法。

http://download.autodesk.com/us/maya/2010help/index.html?url=Python_Python_and_threading.htm,topicNumber=d0e182779

希望这对你有帮助。

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