带单词列表的数值占卜法

Question

我刚开始学习编程，想要把用户输入的数字和文件中单词的数值进行匹配。比如说，a=1，b=2，c=3，A=1，B=2。如果用户输入“2”，那么输出的结果就是所有数值为2的单词。

userinput = raw_input("Please, enter the gematric value of the word: ")
inputfile = open('c:/school/dictionarytest.txt', 'r')
inputfile.lower()
output = []
for word in inputfile:
    userinput = ord(character) - 96
    output.append(character)
    print output
inputfile.close()

我对这些还不是很熟悉，语法也不太懂。有人能帮我一下吗？谢谢！

编辑1 - 比如用户输入数字7。如果列表中有单词“bad”（b=2，a=1，d=4），那么输出就应该是“bad”，还有其他所有字符加起来等于7的单词。

Answer 1

你没有在读取这个文件

inputfile = open('c:/school/dictionarytest.txt', 'r')
file_input = inputfile.readlines().lower()
for character in file_input:
          if userinput == ord(character)-96:
                    output.append(character)

Answer 2

下面是带有详细注释的代码：

# ask user for an input until an integer is provided
prompt = "Please, enter the gematric value of the word: "
while True: # infinite loop
    try:        
        # ask user for an input; convert it to integer immediately
        userinput = int(raw_input(prompt))
    except ValueError: # `int()` can't parse user input as an integer
        print('the gematric value must be an integer. Try again')
    else:
        break # got an integer successfully; exit the loop

# use `with` statement to close the file automatically
# `'r'` is default; you don't need to specify it explicitly
with open(r'c:\school\dictionarytest.txt') as inputfile:
    #XXX inputfile.lower() # WRONG!!! file object doesn't have .lower() method

    # assuming `dictionarytest.txt` has one word per line
    for word in inputfile: # read the file line by line
        word = word.strip() # strip leading/trailing whitespace
        if gematric_value(word) == userinput:
           print(word) # print words that match user input

其中 gematric_value() 函数是：

def gematric_value(word):
    """Sum of numerical values of word's characters.

    a -> 1, b -> 2, c -> 3; A -> 1, B -> 2, etc
    """
    # word is a string; iterating over it produces individual "characters"
    # iterate over lowercased version of the word (due to A == a == 1)
    return sum(ord(c) - ord('a') + 1 for c in word.lower())

注意：在你的代码中不要使用上面的注释风格。这种风格仅适用于学习目的。你应该假设阅读你代码的人对Python是熟悉的。